Elizabeth went on a fabulous vacation in May and racked up a lot of charges on her credit card. When it came time to pay her June credit card bill, she left a balance of $1200. Elizabeth’s credit card billing cycle runs from the nineteenth of each month to the eighteenth of the next month, and her interest rate is 19.5%. She started the billing cycle June 19—July 18 with a previous balance of $1200. In addition, she made three purchases, with the dates and amounts shown in Table 10-11 . On July 15 she made an online payment of $500.00 that was credited to her balance the same day. a. Find the average daily balance on the credit card account for the billing cycle June 19—July 18. b. Compute the interest charged for the billing cycle June 19— July 18. c. Find the new balance on the account at the end of the June 19—July 18 billing cycle. Date Amount of purchase/payment 6/21 $179.58 6/30 $40.00 7/5 $98.35 7/15 Payment $500.00
Elizabeth went on a fabulous vacation in May and racked up a lot of charges on her credit card. When it came time to pay her June credit card bill, she left a balance of $1200. Elizabeth’s credit card billing cycle runs from the nineteenth of each month to the eighteenth of the next month, and her interest rate is 19.5%. She started the billing cycle June 19—July 18 with a previous balance of $1200. In addition, she made three purchases, with the dates and amounts shown in Table 10-11 . On July 15 she made an online payment of $500.00 that was credited to her balance the same day. a. Find the average daily balance on the credit card account for the billing cycle June 19—July 18. b. Compute the interest charged for the billing cycle June 19— July 18. c. Find the new balance on the account at the end of the June 19—July 18 billing cycle. Date Amount of purchase/payment 6/21 $179.58 6/30 $40.00 7/5 $98.35 7/15 Payment $500.00
Elizabeth went on a fabulous vacation in May and racked up a lot of charges on her credit card. When it came time to pay her June credit card bill, she left a balance of $1200. Elizabeth’s credit card billing cycle runs from the nineteenth of each month to the eighteenth of the next month, and her interest rate is 19.5%. She started the billing cycle June 19—July 18 with a previous balance of $1200. In addition, she made three purchases, with the dates and amounts shown in Table 10-11. On July 15 she made an online payment of $500.00 that was credited to her balance the same day.
a. Find the average daily balance on the credit card account for the billing cycle June 19—July 18.
b. Compute the interest charged for the billing cycle June 19— July 18.
c. Find the new balance on the account at the end of the June 19—July 18 billing cycle.
موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
Chapter 10 Solutions
Excursions in Modern Mathematics, Books a la carte edition (9th Edition)
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