Biology
12th Edition
ISBN: 9780078024269
Author: Sylvia Mader, Michael Windelspecht
Publisher: McGraw-Hill Education
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Chapter 10, Problem 5A
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1) Given an mRNA with the following sequence, please translate the codons to a chain of amino acids. Use the codon chart below.5’AUG/CCU/GCU/UAC/CGG/GAG/UAA3’
“met-_________-_________-_________-_________-_________”STOP”
2) Assuming the original polypeptide chain below, match each type of point mutation with the polypeptide chain that results.
Original polypeptide: Pro-Thr-Ser-Leu-Leu-His-Asn
A. Missense
B. Silent
C. Nonsense
D. Frameshift
______ Pro-Thr-Ser-STOP
______ Pro-Thr-Ser-Leu-Ile-His-Asn
______ Pro-Thr-Ser-Leu-Leu-His-Asn
_______ Pro-Thr-His-Cys-Tyr-Thr
a) The relationship between the Hawaiian bobtail squid and V. fischeri is symbiotic where both species benefit. What is the benefit to each?
b) Why might quorum sensing be beneficial to pathogenic bacteria?
c) How might scientists use quorum sensing to treat bacterial infections?
a) What is the function of the disulfide bonds that form within and between the alpha and beta chains?
b) How does proinsulin differ from mature insulin?
c) What organelles are involved in forming mature insulin?
Chapter 10 Solutions
Biology
Ch. 10.1 - Prob. 1CYPCh. 10.1 - Prob. 2CYPCh. 10.1 - Prob. 3CYPCh. 10.2 - Prob. 1CYPCh. 10.2 - Prob. 2CYPCh. 10.2 - Prob. 3CYPCh. 10.3 - Prob. 1CYPCh. 10.3 - Explain what would cause daughter ceils following...Ch. 10.3 - Prob. 3CYPCh. 10.4 - Prob. 1CYP
Ch. 10.4 - 2. Explain how meiosis II is more similar to...Ch. 10.5 - Describe where cells that undergo meiosis are...Ch. 10.5 - Prob. 2CYPCh. 10.6 - 1. Explain the kinds of changes in chromosome...Ch. 10.6 - Prob. 2CYPCh. 10.6 - Prob. 3CYPCh. 10 - Prob. 1NS.1QCCh. 10 - Prob. 1NS.2QCCh. 10 - Prob. 1ACh. 10 - Prob. 2ACh. 10 - Prob. 3ACh. 10 - Prob. 4ACh. 10 - Prob. 5ACh. 10 - Prob. 6ACh. 10 - Prob. 7ACh. 10 - Prob. 8ACh. 10 - Prob. 9ACh. 10 - Prob. 10ACh. 10 - Prob. 11ACh. 10 - Prob. 12ACh. 10 - Prob. 13ACh. 10 - Prob. 14ACh. 10 - Prob. 15ACh. 10 - Prob. 16ACh. 10 - Prob. 17ACh. 10 - Prob. 18ACh. 10 - Prob. 1TSCh. 10 - Prob. 2TSCh. 10 - Prob. 3TSCh. 10 - Prob. 4TS
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- 1)Which plate did you see purple/pink/blue bacterial cells? Why did you see this growth? Explain your answer in terms of transformation and plasmids? 2) Calculating Transformation Efficiency For the +DNA/+Amp/+IPTG plate, record the following: Number of transformants (colonies): _________________ Nanograms of plasmid DNA added: 50 ng Final recovery volume: 0.50 mL Volume plated: 0.25 mL Transformation efficiency equation: Transformation efficiency = Number of transformants / µg of DNA x Final volume at recovery (mL)/ volume plated (mL) 3) Using the equation above, calculate the transformation efficiency. 4) Describe the success of the transformation efficiency of this demo based on the calculation you did above?arrow_forwardOverview of Transformation Protocol -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes. Questions: 1) What differences would you expect to see between the…arrow_forwardOverview of Transformation Protocol -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes. Questions: 1)What is the selectable marker in this experiment? How…arrow_forward
- Based on your results, which suspect's DNA best matches the DNA found at the crime scene?arrow_forwardIn oxidase test with Pseudomonas aeruginosa, the cell cultures on the slide turn colorless to be purple after tetra-methyl-p-phenylenediamine dihydrochloride (TMPD) is added. In the reaction, OTMPD is electron acceptor O cytochrome c is the electron source oxygen is terminal electron acceptor OH2 produced is electron donorarrow_forwardYou will use the following scenario to answer a group of 5 questions. You have isolated a microbe from an environmental sample. The microbe has the ability to perform a new metabolic reaction at a very low temperature, so you are excited that it could be a new species. You have shipped your samples off for sequencing and are now waiting for the results. Out of curiosity (and maybe boredom...) you decide to test your culture for the Catalase and Oxidase enzymes. Upon testing your sample for catalase, you don't see any bubbles; however, you do see a color change to purple during the Oxidase test. What results can you conclude from this? O Catalase-/ Oxidase + O Catalase +/ Oxidase + Catalase + / Oxidase- O Catalase / Oxidase - O None of the abovearrow_forward
- Which of the following is not a strength of using 16S rRNA for phylogenetic analyses? OA. It's cheap OB. It's easy to do C. It can be used to identify all the way down to the strain level OD. Both A & B OE. None of the abovearrow_forwardWhy are molecular approaches important to the field of microbial taxonomy and phylogeny? Phylogenetic inferences based on molecular approaches provide the most robust analysis of microbial evolution currently available. It allows for the collection of a large and accurate dataset from many organisms Almost no fossil record was left by microbes when compared to plants and animals All of the above None of the abovearrow_forwardYou will use the following scenario to answer a group of 5 questions. You have isolated a microbe from an environmental sample. The microbe has the ability to perform a new metabolic reaction at a very low temperature, so you are excited that it could be a new species. You have already cultured it and gone through the plate isolation procedure. Before you ship your samples off for sequencing, you want to do one final check of the A260 ratios. You get back the following ratios: A260/280 ratio is 1.89; A260/230 is 2.01. These ratios are close enough to the accepted "pure" values so they could be considered "pure" and mostly (if not completely) free of contaminants from the PCR process. True Falsearrow_forward
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