Explanation Given: Temperature = 25°C Pressure = 1 atm Volume of nitrogen container = 1.0L Dimension of closet = 1.0m × 1.0×2.0m Density of liquid nitrogen = 0.0807 g mL Formula used: Number of moles= Mass Molar mass PV=nRT where, P = Pressure V= volume n = number of moles T = temperature R = gas constant = 0.0821 Latm molK Percent(by volume)= Volume of nitrogen volume of air × 100 Calculation: Molar mass of nitrogen =28 g mole Let us calculate the mass of nitrogen present Mass= Density * Volume= 0.807 g mole × 1000mL=807 grams Moles of nitrogen present Moles = Mass Molar mass = 807 28 =28...

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ISBN: 9780136444459

Author: Tro

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Chapter 10, Problem 46E

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To determine:

The percent (by volume) of air displaced by the nitrogen.

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Chapter 10, Problem 45E

Chapter 10, Problem 47E

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The percent (by volume) of air displaced by the nitrogen.

Solution Summary: The author calculates the volume of air displaced by nitrogen using the ideal gas equation PV=nRT.

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To determine: The percent (by volume) of air displaced by the nitrogen.

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Chapter 10 Solutions

To determine:

The percent (by volume) of air displaced by the nitrogen.