Twin skaters approach one another as shown in Figure 10.39 and lock hands. (a) Calculate their final angular velocity , given each had an initial speed of 2.50 m/s relative to the ice. Each has a mass of 70.0 kg, and each has a center of mass located 0.800 m from their locked hands. You may approximate their moments of inertia to be that of point masses at this radius. (b) Compare the initial kinetic energy and final kinetic energy.
Twin skaters approach one another as shown in Figure 10.39 and lock hands. (a) Calculate their final angular velocity , given each had an initial speed of 2.50 m/s relative to the ice. Each has a mass of 70.0 kg, and each has a center of mass located 0.800 m from their locked hands. You may approximate their moments of inertia to be that of point masses at this radius. (b) Compare the initial kinetic energy and final kinetic energy.
Twin skaters approach one another as shown in Figure 10.39 and lock hands. (a) Calculate their final angular velocity, given each had an initial speed of 2.50 m/s relative to the ice. Each has a mass of 70.0 kg, and each has a center of mass located 0.800 m from their locked hands. You may approximate their moments of inertia to be that of point masses at this radius. (b) Compare the initial kinetic energy and final kinetic energy.
Definition Definition Rate of change of angular velocity. Angular acceleration indicates how fast the angular velocity changes over time. It is a vector quantity and has both magnitude and direction. Magnitude is represented by the length of the vector and direction is represented by the right-hand thumb rule. An angular acceleration vector will be always perpendicular to the plane of rotation. Angular acceleration is generally denoted by the Greek letter α and its SI unit is rad/s 2 .
3.63 • Leaping the River II. A physics professor did daredevil
stunts in his spare time. His last stunt was an attempt to jump across
a river on a motorcycle (Fig. P3.63). The takeoff ramp was inclined at
53.0°, the river was 40.0 m wide, and the far bank was 15.0 m lower
than the top of the ramp. The river itself was 100 m below the ramp.
Ignore air resistance. (a) What should his speed have been at the top of
the ramp to have just made it to the edge of the far bank? (b) If his speed
was only half the value found in part (a), where did he land?
Figure P3.63
53.0°
100 m
40.0 m→
15.0 m
Please solve and answer the question correctly please. Thank you!!
You throw a small rock straight up from the edge of a highway bridge that crosses a river. The rock passes you on its way down, 5.00 s after it was thrown. What is the speed of the rock just before it reaches the water 25.0 m below the point where the rock left your hand? Ignore air resistance.
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