Explanation Given: Volume of the cylinder = 28.5 L Pressure of oxygen gas inside the cylinder = 1.8 atm Temperature of gas inside the cylinder = 298 K Formula used: According to ideal gas law , PV = nRT Here, P = pressure of a gas V = volume of the gas n = moles of the gas R = gas constant T = temperature of the gas in Kelvin scale Calculation: Here, P = pressure of oxygen gas = 1.8 atm V = volume of the gas = 28.5 L n = moles of the gas =? R = gas constant = 0.082 L.atm/K...

Chemistry: Structure and Properties (2nd Edition)

2nd Edition

ISBN: 9780134293936

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 10, Problem 41E

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To determine:

Moles of oxygen gas in a cylinder containing 28.5 L of oxygen at a pressure of 1.8 atm and a temperature of 298 K.

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Chapter 10, Problem 40E

Chapter 10, Problem 42E

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Chapter 10 Solutions

Chemistry: Structure and Properties (2nd Edition)

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Moles of oxygen gas in a cylinder containing 28.5 L of oxygen at a pressure of 1.8 atm and a temperature of 298 K.

Solution Summary: The author explains that there are 2 moles of oxygen gas in a cylinder with 1.8 atm pressure and 298 K temperature.

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To determine: Moles of oxygen gas in a cylinder containing 28.5 L of oxygen at a pressure of 1.8 atm and a temperature of 298 K.

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Chapter 10 Solutions

To determine:

Moles of oxygen gas in a cylinder containing 28.5 L of oxygen at a pressure of 1.8 atm and a temperature of 298 K.