Explanation Given: Pressure of spherical bubble at the depth P 1 =4 atm Radius of spherical bubble at the depth r 1 =2.5 cm Pressure at the surface P 2 =1 atm Here, according to the given question, we can see that the temperature is constant. Now, at constant temperature we can use Boyle’s law which states that at constant temperature pressure is inversely proportional to volume. Pα 1 V PV=constant Now the pressure at the depth P 1 and volume of the spherical bubble V 1 reaches the surface having pressure P 2 and the volume of the spherical bubble becomes V 2 .then applying Boyle’s law we get P 1 V 1 =P 2 V 2 Since the bubble is spherical, so the volume of the bubble is equivalent to the volume of the sphere. Formula used: The volume of the sphere V= 4/3 °r 3 Boyle’s law at constant temperature T Pα 1 V PV=constant

Chemistry: Structure and Properties (2nd Edition)

2nd Edition

ISBN: 9780134293936

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 10, Problem 115E

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The radius of the bubble when it reached the surface of water

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Chapter 10, Problem 114E

Chapter 10, Problem 116E

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Chemistry: Structure and Properties (2nd Edition)

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The radius of the bubble when it reached the surface of water

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To determine:

The radius of the bubble when it reached the surface of water