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a)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
b)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
c)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
d)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
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Chapter 10 Solutions
Bundle: Chemistry, Loose-leaf Version, 10th + Enhanced Webassign Printed Access Card For Chemistry, Multi-term Courses
- Use the literature Ka value of the acetic acid, and the data below to answer these questions. Note: You will not use the experimental titration graphs to answer the questions that follow. Group #1: Buffer pH = 4.35 Group #2: Buffer pH = 4.70 Group #3: Buffer pH = 5.00 Group #4: Buffer pH = 5.30 Use the Henderson-Hasselbalch equation, the buffer pH provided and the literature pKa value of acetic acid to perform the following: a) calculate the ratios of [acetate]/[acetic acid] for each of the 4 groups buffer solutions above. b) using the calculated ratios, which group solution will provide the best optimal buffer (Hint: what [acetate]/[acetic acid] ratio value is expected for an optimal buffer?) c) explain your choicearrow_forwardHow would you prepare 1 liter of a 50 mM Phosphate buffer at pH 7.5 beginning with K3PO4 and 1 M HCl or 1 M NaOH? Please help and show calculations. Thank youarrow_forwardDraw the four most importantcontributing structures of the cation intermediate thatforms in the electrophilic chlorination of phenol,(C6H5OH) to form p-chlorophenol. Put a circle aroundthe best one. Can you please each step and also how you would approach a similar problem. Thank you!arrow_forward
- A 100mM lactic acid/lactate buffer was found to have a lactate to lactic acid ratio of 2 and a pH of 4.2. What is the pKa of lactic acid? Can you please help show the calculations?arrow_forwardUsing line angle formulas, draw thestructures of and name four alkanes that have total of 7carbons, one of which is tertiary.Please explain this in detail and can you also explain how to approach a similar problem like this as well?arrow_forwardUsing dashed line wedge projections drawthe indicated compounds and indicate whether thecompound you have drawn is R or S.(a) The two enantiomers of 2-chlorobutane. Can you please explain your steps and how you would approach a similar problem. Thank you!arrow_forward
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