
Concept explainers
(a)
To determine: The structural aspect of the 18-carbon fatty acids can be correlated to the melting point
Introduction:
Fatty acids are a class of lipids. They are non-polar compound this means they can only dissolve in non-polar solvents such as benzene, diethyl ether, and hexane. Fatty acids can be saturated or unsaturated. Saturated fatty acids are those which do no possess any double bond in its structure, For example: Palmitic acid and stearic acid. While unsaturated fatty acids possess one or more double bonds, For example: Oleic acid and linoleic acid.
(b)
To draw: The possible triacyglycerols that can be constructed from glycerol, palmitic acid, and oleic acid, and also rank them in order of increasing melting point.
Introduction:
Fatty acids are a class of lipids. They are non-polar compound this means they can only dissolve in non-polar solvents such as benzene, diethyl ether, and hexane. Fatty acids can be saturated or unsaturated. Saturated fatty acids are those which do no possess any double bond in its structure, For example: Palmitic acid and stearic acid. While unsaturated fatty acids possess one or more double bonds, For example: Oleic acid and linoleic acid.
(c)
To determine: The presence or absence of branched-chain fatty acid increase or decrease the fluidity of the membrane.
Introduction:
Fatty acids are a class of lipids. They are non-polar compound this means they can only dissolve in non-polar solvents such as benzene, diethyl ether, and hexane. Fatty acids can be saturated or unsaturated. Saturated fatty acids are those which do no possess any double bond in its structure, For example: Palmitic acid and stearic acid. While unsaturated fatty acids possess one or more double bonds, For example: Oleic acid and linoleic acid.

Want to see the full answer?
Check out a sample textbook solution
Chapter 10 Solutions
EBK LEHNINGER PRINCIPLES OF BIOCHEMISTR
- 4. Read paragraph 4.15 from your textbook, use your calculated lattice energy values for CuO, CuCO3 and Cu(OH)2 an explain thermal decomposition reaction of malachite: Cu2CO3(OH)2 →2CuO + H2O + CO2 (3 points)arrow_forwardPlease sirrr soollveee these parts pleaseeee and thank youuuuuarrow_forwardIII O Organic Chemistry Using wedges and dashes in skeletal structures Draw a skeletal ("line") structure for each of the molecules below. Be sure your structures show the important difference between the molecules. key O O O O O CHON Cl jiii iiiiiiii You can drag the slider to rotate the molecules. Explanation Check Click and drag to start drawing a structure. Q Search X G ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use F 3 W C 3/5arrow_forward
- 3. Use Kapustinskii's equation and data from Table 4.10 in your textbook to calculate lattice energies of Cu(OH)2 and CuCO3 (4 points)arrow_forward2. Copper (II) oxide crystalizes in monoclinic unit cell (included below; blue spheres 2+ represent Cu²+, red - O²-). Use Kapustinski's equation (4.5) to calculate lattice energy for CuO. You will need some data from Resource section of your textbook (p.901). (4 points) CuOarrow_forwardWhat is the IUPAC name of the following compound? OH (2S, 4R)-4-chloropentan-2-ol O (2R, 4R)-4-chloropentan-2-ol O (2R, 4S)-4-chloropentan-2-ol O(2S, 4S)-4-chloropentan-2-olarrow_forward
- Use the reaction coordinate diagram to answer the below questions. Type your answers into the answer box for each question. (Watch your spelling) Energy A B C D Reaction coordinate E A) Is the reaction step going from D to F endothermic or exothermic? A F G B) Does point D represent a reactant, product, intermediate or transition state? A/ C) Which step (step 1 or step 2) is the rate determining step? Aarrow_forward1. Using radii from Resource section 1 (p.901) and Born-Lande equation, calculate the lattice energy for PbS, which crystallizes in the NaCl structure. Then, use the Born-Haber cycle to obtain the value of lattice energy for PbS. You will need the following data following data: AH Pb(g) = 196 kJ/mol; AHƒ PbS = −98 kJ/mol; electron affinities for S(g)→S¯(g) is -201 kJ/mol; S¯(g) (g) is 640kJ/mol. Ionization energies for Pb are listed in Resource section 2, p.903. Remember that enthalpies of formation are calculated beginning with the elements in their standard states (S8 for sulfur). The formation of S2, AHF: S2 (g) = 535 kJ/mol. Compare the two values, and explain the difference. (8 points)arrow_forwardIn the answer box, type the number of maximum stereoisomers possible for the following compound. A H H COH OH = H C Br H.C OH CHarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





