ENGINEERING ECONOMIC ENHANCED EBOOK
14th Edition
ISBN: 9780190931940
Author: NEWNAN
Publisher: OXF
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Question
Chapter 10, Problem 39P
a)
To determine
To find: Expected savings per year, expected life and corresponding
b)
To determine
To find: Present worth of each combination of savings per year and life.
c)
To determine
To Elaborate: Reasons for matching of answers derived in sub part (a) and (b)
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FORMULAS:
A new engineer is evaluating whether to
use a larger diameter pipe for a water line.
The pipe will cost $376,183 more initially but
will reduce pumping costs. The optimistic,
most likely, and pessimistic projections for
annual savings are $30,000, $20,000, and
$5000, with respective probabilities of 20%,
50%, and 30%. The interest rate is equally
likely to be 6% or 8% (use 7% as most likely),
and the water line should have a life of 40
years.
a) Find the PW for the pessimistic case, the
most likely case, and the optimistic case.
Then determine the Expected PW based on
these.
b) Find the expected annual savings and
the expected interest rate. Determine the
Expected PW based on these.
Eng. Economic Q1. Would a dollar tomorrow be worth more to you today when interested is 20% or 10%?
Air pollution in the country of Gawanza has grown over the last ten years with an increase in manufacturing industries. The government of Gawanza now has a plan to reduce the CO2 emissions into the air by 10% per year over the next 10 years. What do you expect will happen?
Group of answer choices
The cost and benefits to Gawanza will be lowest in the last few years of implementing this plan.
The cost and benefits to Gawanza will be highest in the last few years of implementing this plan.
The cost will be the highest and benefits the lowest in year ten.
Chapter 10 Solutions
ENGINEERING ECONOMIC ENHANCED EBOOK
Ch. 10 - Prob. 1QTCCh. 10 - Prob. 2QTCCh. 10 - Prob. 3QTCCh. 10 - Prob. 1PCh. 10 - Prob. 2PCh. 10 - Prob. 3PCh. 10 - Prob. 4PCh. 10 - Prob. 5PCh. 10 - Prob. 6PCh. 10 - Prob. 7P
Ch. 10 - Prob. 8PCh. 10 - Prob. 9PCh. 10 - Prob. 10PCh. 10 - Prob. 11PCh. 10 - Prob. 12PCh. 10 - Prob. 13PCh. 10 - Prob. 14PCh. 10 - Prob. 15PCh. 10 - Prob. 16PCh. 10 - Prob. 17PCh. 10 - Prob. 18PCh. 10 - Prob. 19PCh. 10 - Prob. 20PCh. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Prob. 29PCh. 10 - Prob. 30PCh. 10 - Prob. 31PCh. 10 - Prob. 32PCh. 10 - Prob. 33PCh. 10 - Prob. 34PCh. 10 - Prob. 35PCh. 10 - Prob. 36PCh. 10 - Prob. 37PCh. 10 - Prob. 38PCh. 10 - Prob. 39PCh. 10 - Prob. 40PCh. 10 - Prob. 41PCh. 10 - Prob. 42PCh. 10 - Prob. 43PCh. 10 - Prob. 44PCh. 10 - Prob. 45PCh. 10 - Prob. 46PCh. 10 - Prob. 47PCh. 10 - Prob. 48PCh. 10 - Prob. 49PCh. 10 - Prob. 50PCh. 10 - Prob. 51PCh. 10 - Prob. 52PCh. 10 - Prob. 53PCh. 10 - Prob. 54PCh. 10 - Prob. 55PCh. 10 - Prob. 56PCh. 10 - Prob. 57PCh. 10 - Prob. 58PCh. 10 - Prob. 59PCh. 10 - Prob. 60PCh. 10 - Prob. 61PCh. 10 - Prob. 62PCh. 10 - Prob. 63PCh. 10 - Prob. 64PCh. 10 - Prob. 65P
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