Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 10, Problem 24P
Two balls with masses M and m are connected by a rigid rod of length L, and negligible mass as shown in Figure P10.24. For an axis perpendicular to the rod. (a) show that the system has the minimum moment of inertia when the axis passes through the center of mass. (b) Show that this moment of inertia is I = μL2, where μ = mM/(m + M).
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Please help with calculating the impusle, thanks!
Having calculated the impact and rebound velocities of the ping pong ball and the tennis ball calculate the rebounding impulse:
1.Measure the weight of the balls and determine their mass.
Tennis ball: 0.57 kg Ping Pong Ball: 0.00246 kg
The impulse, I, is equal to the change in momentum, Pf-Pi. Note the sign change, i.e., going down is negative and up is positive. The unit for momentum is kg-m/s. The change is momentum, impulse, is often givens the equivalent unit of N-S, Newton-Second
Chapter 10 Solutions
Physics for Scientists and Engineers with Modern Physics
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Moment of Inertia; Author: Physics with Professor Matt Anderson;https://www.youtube.com/watch?v=ZrGhUTeIlWs;License: Standard Youtube License