Discovering Computers ©2018: Digital Technology, Data, and Devices
1st Edition
ISBN: 9781337285100
Author: Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Jennifer T. Campbell, Mark Frydenberg
Publisher: Cengage Learning
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Chapter 10, Problem 20CT
Program Plan Intro
Broadband wireless service:
- It is one of the newer technologies to provide internet services using fixed point wireless loop.
- In this technology, the data are transmitted over very high radio frequencies by bypassing the telephone company local loop.
- The broadband transmissions are transmitted from the satellite system or high-speed internet connection in the land for the broadband service provider.
- The local transmission antenna (base stations) receives the broadband transmissions and then, the receiver dish in the tall building tower receives the transmissions and converts these signals to provide internet service for home and businesses.
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1.[30 pts] Computers generate color pictures on a video screen or liquid crystal display by
mixing three different colors of light: red, green, and blue. Imagine a simple scheme, with
three different lights, each of which can be turned on or off, projecting onto a glass screen:
We can create eight different colors based on the absence (0) or presence (1) of light
sources R,G and B:
R
G
B
Color
0
0
0
Black
0
0
1
Blue
0
1
0
Green
0
1
1
Cyan
1
0
0
Red
1
0
1
Magenta
1
1
1
0
Yellow
1
White
1
Each of these colors can be represented as a bit vector of length 3, and we can apply
Boolean operations to them.
a. The complement of a color is formed by turning off the lights that are on and turning
on the lights that are off. What would be the complement of each of the eight colors
listed above?
b. Describe the effect of applying Boolean operations on the following colors:
Λ
1. Red(100) ^ Magenta(101)= Blue(001)
2. Bue(001) | Green(010)=
3. Yellow(100) & Cyan(011)=
2.[30 pts] Perform the following…
D. S. Malik, Data Structures Using C++, 2nd Edition, 2010
Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
There are two methods, method #1 which calculates the square root for positive integers, and
method #2, which calculates the square root of positive doubles (also works for integers).
public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
}
Program-it-Yourself: In the main method, create a program that…
Chapter 10 Solutions
Discovering Computers ©2018: Digital Technology, Data, and Devices
Ch. 10 - Prob. 1SGCh. 10 - Prob. 2SGCh. 10 - Prob. 3SGCh. 10 - Prob. 4SGCh. 10 - Prob. 5SGCh. 10 - Prob. 6SGCh. 10 - Prob. 7SGCh. 10 - Prob. 8SGCh. 10 - Prob. 9SGCh. 10 - Prob. 10SG
Ch. 10 - Prob. 11SGCh. 10 - Prob. 12SGCh. 10 - Prob. 13SGCh. 10 - Prob. 14SGCh. 10 - Prob. 15SGCh. 10 - Prob. 16SGCh. 10 - Prob. 17SGCh. 10 - Prob. 18SGCh. 10 - Prob. 19SGCh. 10 - Prob. 20SGCh. 10 - Prob. 21SGCh. 10 - Prob. 22SGCh. 10 - Prob. 23SGCh. 10 - Prob. 24SGCh. 10 - Prob. 25SGCh. 10 - Prob. 26SGCh. 10 - Prob. 27SGCh. 10 - Prob. 28SGCh. 10 - Prob. 29SGCh. 10 - Prob. 30SGCh. 10 - Prob. 31SGCh. 10 - Prob. 32SGCh. 10 - Prob. 33SGCh. 10 - Prob. 34SGCh. 10 - Prob. 35SGCh. 10 - Prob. 36SGCh. 10 - Prob. 37SGCh. 10 - Prob. 38SGCh. 10 - Prob. 39SGCh. 10 - Prob. 40SGCh. 10 - Prob. 41SGCh. 10 - Prob. 42SGCh. 10 - Prob. 43SGCh. 10 - Prob. 44SGCh. 10 - Prob. 45SGCh. 10 - Prob. 46SGCh. 10 - Prob. 47SGCh. 10 - Prob. 48SGCh. 10 - Prob. 49SGCh. 10 - Prob. 1TFCh. 10 - Prob. 2TFCh. 10 - Prob. 3TFCh. 10 - Prob. 4TFCh. 10 - Prob. 5TFCh. 10 - Prob. 6TFCh. 10 - Prob. 7TFCh. 10 - Prob. 8TFCh. 10 - Prob. 9TFCh. 10 - Prob. 10TFCh. 10 - Prob. 11TFCh. 10 - Prob. 12TFCh. 10 - Prob. 1MCCh. 10 - Prob. 2MCCh. 10 - Prob. 3MCCh. 10 - Prob. 4MCCh. 10 - Prob. 5MCCh. 10 - Prob. 6MCCh. 10 - Prob. 7MCCh. 10 - Prob. 8MCCh. 10 - Prob. 1MCh. 10 - Prob. 2MCh. 10 - Prob. 3MCh. 10 - Prob. 4MCh. 10 - Prob. 5MCh. 10 - Prob. 6MCh. 10 - Prob. 7MCh. 10 - Prob. 8MCh. 10 - Prob. 9MCh. 10 - Prob. 10MCh. 10 - Prob. 2CTCh. 10 - Prob. 3CTCh. 10 - Prob. 4CTCh. 10 - Prob. 5CTCh. 10 - Prob. 6CTCh. 10 - Prob. 7CTCh. 10 - Prob. 8CTCh. 10 - Prob. 9CTCh. 10 - Prob. 10CTCh. 10 - Prob. 11CTCh. 10 - Prob. 12CTCh. 10 - Prob. 13CTCh. 10 - Prob. 14CTCh. 10 - Prob. 15CTCh. 10 - Prob. 16CTCh. 10 - Prob. 17CTCh. 10 - Prob. 18CTCh. 10 - Prob. 19CTCh. 10 - Prob. 20CTCh. 10 - Prob. 21CTCh. 10 - Prob. 22CTCh. 10 - Prob. 23CTCh. 10 - Prob. 24CTCh. 10 - Prob. 25CTCh. 10 - Prob. 26CTCh. 10 - Prob. 27CTCh. 10 - Prob. 1PSCh. 10 - Prob. 2PSCh. 10 - Prob. 3PSCh. 10 - Prob. 4PSCh. 10 - Prob. 5PSCh. 10 - Prob. 6PSCh. 10 - Prob. 7PSCh. 10 - Prob. 8PSCh. 10 - Prob. 9PSCh. 10 - Prob. 10PSCh. 10 - Prob. 11PSCh. 10 - Prob. 1.1ECh. 10 - Prob. 1.2ECh. 10 - Prob. 1.3ECh. 10 - Prob. 2.1ECh. 10 - Prob. 2.2ECh. 10 - Prob. 2.3ECh. 10 - Prob. 3.1ECh. 10 - Prob. 3.2ECh. 10 - Prob. 3.3ECh. 10 - Prob. 4.1ECh. 10 - Prob. 4.2ECh. 10 - Prob. 4.3ECh. 10 - Prob. 1IRCh. 10 - Prob. 2IRCh. 10 - Prob. 3IRCh. 10 - Prob. 4IRCh. 10 - Prob. 5IRCh. 10 - Prob. 1CTQCh. 10 - Prob. 2CTQCh. 10 - Prob. 3CTQCh. 10 - Prob. 4CTQ
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