Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
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Question
Chapter 10, Problem 19KT
Interpretation Introduction
Interpretation:
The key term corresponding to the definition “a theoretical gas that obeys the kinetic theory under all conditions” is to be stated.
Concept introduction:
The
The ideal gas equation resultant of all the ideal gas law’s is shown below.
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יווי
10
20
30
40
50
60
70
3.5
3
2.5
2
1.5
1
[ppm]
3.5
3
2.5
2
1.5
1
6 [ppm]
1
1.5
-2.5
3.5
2H2S(g)+3O2(g)→2SO2(g)+2H2O(g)
A 1.2mol sample of H2S(g) is combined with excess O2(g), and the reaction goes to completion.
Question
Which of the following predicts the theoretical yield of SO2(g) from the reaction?
Responses
1.2 g
Answer A: 1.2 grams
A
41 g
Answer B: 41 grams
B
77 g
Answer C: 77 grams
C
154 g
Answer D: 154 grams
D
Part VII. Below are the 'HNMR, 13 C-NMR, COSY 2D- NMR, and HSQC 2D-NMR (similar with HETCOR but axes are reversed) spectra of an
organic compound with molecular formula C6H1003 - Assign chemical shift values to the H and c atoms of the
compound. Find the structure. Show complete solutions.
Predicted 1H NMR Spectrum
4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1
f1 (ppm)
Predicted 13C NMR Spectrum
100
f1 (ppm)
30
220 210 200 190 180
170
160 150 140 130 120
110
90
80
70
-26
60
50
40
46
30
20
115
10
1.0 0.9 0.8
0
-10
Chapter 10 Solutions
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Ch. 10 - Prob. 1CECh. 10 - Prob. 2CECh. 10 - Prob. 3CECh. 10 - Prob. 4CECh. 10 - Prob. 5CECh. 10 - Prob. 6CECh. 10 - Prob. 7CECh. 10 - Prob. 8CECh. 10 - Prob. 9CECh. 10 - Prob. 10CE
Ch. 10 - Prob. 1KTCh. 10 - Prob. 2KTCh. 10 - Prob. 3KTCh. 10 - Prob. 4KTCh. 10 - Prob. 5KTCh. 10 - Prob. 6KTCh. 10 - Prob. 7KTCh. 10 - Prob. 8KTCh. 10 - Prob. 9KTCh. 10 - Prob. 10KTCh. 10 - Prob. 11KTCh. 10 - Prob. 12KTCh. 10 - Prob. 13KTCh. 10 - Prob. 14KTCh. 10 - Prob. 15KTCh. 10 - Prob. 16KTCh. 10 - Prob. 17KTCh. 10 - Prob. 18KTCh. 10 - Prob. 19KTCh. 10 - Prob. 20KTCh. 10 - Prob. 21KTCh. 10 - Prob. 22KTCh. 10 - Prob. 23KTCh. 10 - Prob. 24KTCh. 10 - Prob. 1ECh. 10 - Prob. 2ECh. 10 - Prob. 3ECh. 10 - Prob. 4ECh. 10 - Prob. 5ECh. 10 - Prob. 6ECh. 10 - Prob. 7ECh. 10 - Prob. 8ECh. 10 - Prob. 9ECh. 10 - Prob. 10ECh. 10 - Prob. 11ECh. 10 - Prob. 12ECh. 10 - Prob. 13ECh. 10 - Prob. 14ECh. 10 - Prob. 15ECh. 10 - Prob. 16ECh. 10 - Prob. 17ECh. 10 - Prob. 18ECh. 10 - Prob. 19ECh. 10 - Prob. 20ECh. 10 - Prob. 21ECh. 10 - Prob. 22ECh. 10 - Prob. 23ECh. 10 - Prob. 24ECh. 10 - Prob. 25ECh. 10 - Prob. 26ECh. 10 - Prob. 27ECh. 10 - Prob. 28ECh. 10 - Prob. 29ECh. 10 - Prob. 30ECh. 10 - Prob. 31ECh. 10 - Prob. 32ECh. 10 - Prob. 33ECh. 10 - Prob. 34ECh. 10 - Prob. 35ECh. 10 - Prob. 36ECh. 10 - Prob. 37ECh. 10 - Prob. 38ECh. 10 - Prob. 39ECh. 10 - Prob. 40ECh. 10 - Prob. 41ECh. 10 - Prob. 42ECh. 10 - Prob. 43ECh. 10 - Prob. 44ECh. 10 - Prob. 45ECh. 10 - Prob. 46ECh. 10 - Prob. 47ECh. 10 - Prob. 48ECh. 10 - Prob. 49ECh. 10 - Prob. 50ECh. 10 - Prob. 51ECh. 10 - Prob. 52ECh. 10 - Prob. 53ECh. 10 - Prob. 54ECh. 10 - Prob. 55ECh. 10 - Prob. 56ECh. 10 - Prob. 57ECh. 10 - Prob. 58ECh. 10 - Prob. 59ECh. 10 - Prob. 60ECh. 10 - Prob. 61ECh. 10 - Prob. 62ECh. 10 - Prob. 63ECh. 10 - Prob. 64ECh. 10 - Prob. 65ECh. 10 - Prob. 66ECh. 10 - Prob. 67ECh. 10 - Prob. 68ECh. 10 - Prob. 69ECh. 10 - Prob. 70ECh. 10 - Prob. 71ECh. 10 - Prob. 72ECh. 10 - Prob. 73ECh. 10 - Prob. 74ECh. 10 - Prob. 75ECh. 10 - Prob. 76ECh. 10 - Prob. 77ECh. 10 - Prob. 78ECh. 10 - Prob. 79ECh. 10 - Prob. 80ECh. 10 - Prob. 81ECh. 10 - Prob. 82ECh. 10 - Prob. 83ECh. 10 - Prob. 84ECh. 10 - Prob. 1STCh. 10 - Prob. 2STCh. 10 - Prob. 3STCh. 10 - Prob. 4STCh. 10 - Prob. 5STCh. 10 - Prob. 6STCh. 10 - Prob. 7STCh. 10 - Prob. 8STCh. 10 - Prob. 9STCh. 10 - Prob. 10STCh. 10 - Prob. 11STCh. 10 - Prob. 12STCh. 10 - Prob. 13STCh. 10 - Prob. 14STCh. 10 - Prob. 15STCh. 10 - Prob. 16STCh. 10 - Prob. 17STCh. 10 - Prob. 18STCh. 10 - Prob. 19ST
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