Chapter 10, Problem 16SR

Write equations showing the ions present after the following strong electrolytes are dissolved in water.

a. HNO₃

b. Na₂SO₄

c. Al(NO₃)₃

d. SrBr₂

e. KClO₄

f. NH₄Br

g. NH₄NO₃

h. CuSO₄

i. NaOH

Interpretation Introduction

Interpretation: The equations for the following strong electrolytes have to be written.

Concept Introduction:

A strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.

Answer to Problem 16SR

${\text{HNO}}_{\text{3(l)}}\to {\text{H}}^{\text{+}}{}_{\left(\text{aq}\right)}{\text{+NO}}_{\text{3}}{{}^{\text{-}}}_{\left(\text{aq}\right)}$

Explanation of Solution

To write the dissociation equation of ${\text{HNO}}_{\text{3}}$

The dissociation equation of ${\text{HNO}}_{\text{3}}$ is given as,

${\text{HNO}}_{\text{3(l)}}\to {\text{H}}^{\text{+}}{}_{\left(\text{aq}\right)}{\text{+NO}}_{\text{3}}{{}^{\text{-}}}_{\left(\text{aq}\right)}$

Nitric acid on dissolving in Water split into ${\text{H}}^{\text{+}}$ and ${\text{NO}}_{\text{3}}{}^{\text{-}}$ ions.

Interpretation Introduction

Interpretation: The equations for the following strong electrolytes have to be written.

Concept Introduction:

A strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.

Answer to Problem 16SR

${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4(s)}}\to {\text{2Na}}^{\text{+}}{}_{\left(\text{aq}\right)}{\text{+SO}}_{\text{4}}{{}^{\text{2-}}}_{\left(\text{aq}\right)}$

Explanation of Solution

To write the dissociation equation of ${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4}}$

The dissociation equation of ${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4}}$ is given as,

${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4(s)}}\to {\text{2Na}}^{\text{+}}{}_{\left(\text{aq}\right)}{\text{+SO}}_{\text{4}}{{}^{\text{2-}}}_{\left(\text{aq}\right)}$

Sodium sulphate on dissolving with Water split into ${\text{Na}}^{\text{+}}$ and ${\text{SO}}_{\text{4}}{}^{\text{2-}}$ ions.

Interpretation Introduction

Interpretation: The equations for the following strong electrolytes have to be written.

Concept Introduction:

A strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.

Answer to Problem 16SR

${\text{Al(NO}}_{\text{3}}{\text{)}}_{\text{3(s)}}\to {\text{Al}}^{\text{3+}}{}_{\left(\text{aq}\right)}{\text{+3NO}}_{\text{3}}{{}^{\text{-}}}_{\left(\text{aq}\right)}$

Explanation of Solution

To write the dissociation equation of ${\text{Al(NO}}_{\text{3}}{\text{)}}_3$

The dissociation equation of ${\text{Al(NO}}_{\text{3}}{\text{)}}_3$ is given as,

${\text{Al(NO}}_{\text{3}}{\text{)}}_{\text{3(s)}}\to {\text{Al}}^{\text{3+}}{}_{\left(\text{aq}\right)}{\text{+3NO}}_{\text{3}}{{}^{\text{-}}}_{\left(\text{aq}\right)}$

Aluminum nitrate on dissolving with Water split into ${\text{Al}}^{\text{3+}}$ and ${\text{NO}}_{\text{3}}{}^{\text{-}}$ ions.

Interpretation Introduction

Interpretation: The equations for the following strong electrolytes have to be written.

Concept Introduction:

A strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.

Answer to Problem 16SR

${\text{SrBr}}_{\text{2(s)}}\to {\text{Sr}}^{\text{2+}}{}_{\left(\text{aq}\right)}{\text{+2Br}}^{\text{-}}{}_{\left(\text{aq}\right)}$

Explanation of Solution

To write the dissociation equation of ${\text{SrBr}}_{\text{2}}$

The dissociation equation of ${\text{SrBr}}_{\text{2}}$ is given as,

${\text{SrBr}}_{\text{2(s)}}\to {\text{Sr}}^{\text{2+}}{}_{\left(\text{aq}\right)}{\text{+2Br}}^{\text{-}}{}_{\left(\text{aq}\right)}$

Strontium bromide on dissolving with Water split into ${\text{Sr}}^{\text{2+}}$ and ${\text{Br}}^{\text{-}}$ ions.

Interpretation Introduction

Interpretation: The equations for the following strong electrolytes have to be written.

Concept Introduction:

A strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.

Answer to Problem 16SR

${\text{KClO}}_{\text{4(s)}}\to {\text{K}}^{\text{+}}{}_{\left(\text{aq}\right)}{\text{+ClO}}_{\text{4}}{{}^{\text{-}}}_{\left(\text{aq}\right)}$

Explanation of Solution

To write the dissociation equation of ${\text{KClO}}_{\text{4}}$

The dissociation equation of ${\text{KClO}}_{\text{4}}$ is given as,

${\text{KClO}}_{\text{4(s)}}\to {\text{K}}^{\text{+}}{}_{\left(\text{aq}\right)}{\text{+ClO}}_{\text{4}}{{}^{\text{-}}}_{\left(\text{aq}\right)}$

Potassium perchlorate on dissolving with Water split into ${\text{K}}^{\text{+}}$ and ${\text{ClO}}_{\text{4}}{}^{\text{-}}$ ions.

Interpretation Introduction

Interpretation: The equations for the following strong electrolytes have to be written.

Concept Introduction:

A strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.

Answer to Problem 16SR

${\text{NH}}_{\text{4}}{\text{Br}}_{\left(\text{s}\right)}\to {\text{NH}}_{\text{4}}{{}^{\text{+}}}_{\text{(aq)}}{\text{+Br}}^{\text{-}}{}_{\left(\text{aq}\right)}$

Explanation of Solution

To write the dissociation equation of ${\text{NH}}_{\text{4}}\text{Br}$

The dissociation equation of ${\text{NH}}_{\text{4}}\text{Br}$ is given as,

${\text{NH}}_{\text{4}}{\text{Br}}_{\left(\text{s}\right)}\to {\text{NH}}_{\text{4}}{{}^{\text{+}}}_{\text{(aq)}}{\text{+Br}}^{\text{-}}{}_{\left(\text{aq}\right)}$

Ammonium bromide on dissolving with Water split into ${\text{NH}}_{\text{4}}{}^{\text{+}}$ and ${\text{Br}}^{\text{-}}$

Interpretation Introduction

Interpretation: The equations for the following strong electrolytes have to be written.

Concept Introduction:

A strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.

Answer to Problem 16SR

${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3(s)}}\to {\text{NH}}_{\text{4}}{{}^{\text{+}}}_{\left(\text{aq}\right)}{\text{+NO}}_{\text{3}}{{}^{\text{-}}}_{\left(\text{aq}\right)}$

Explanation of Solution

To write the dissociation equation of ${\text{NH}}_{\text{4}}{\text{NO}}_3$

The dissociation equation of ${\text{NH}}_{\text{4}}{\text{NO}}_3$ is given as,

${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3(s)}}\to {\text{NH}}_{\text{4}}{{}^{\text{+}}}_{\left(\text{aq}\right)}{\text{+NO}}_{\text{3}}{{}^{\text{-}}}_{\left(\text{aq}\right)}$

Ammonium nitrate on dissolving with Water split into ${\text{NH}}_{\text{4}}{}^{\text{+}}$ and ${\text{NO}}_{\text{3}}{}^{\text{-}}$

Interpretation Introduction

Interpretation: The equations for the following strong electrolytes have to be written.

Concept Introduction:

A strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.

Answer to Problem 16SR

${\text{CuSO}}_{\text{4(s)}}\to {\text{Cu}}^{\text{2+}}{}_{\left(\text{aq}\right)}{\text{+SO}}_{\text{4}}{{}^{\text{2-}}}_{\left(\text{aq}\right)}$

Explanation of Solution

To write the dissociation equation of ${\text{CuSO}}_4$

The dissociation equation of ${\text{CuSO}}_4$ is given as,

${\text{CuSO}}_{\text{4(s)}}\to {\text{Cu}}^{\text{2+}}{}_{\left(\text{aq}\right)}{\text{+SO}}_{\text{4}}{{}^{\text{2-}}}_{\left(\text{aq}\right)}$

Copper sulphate on dissolving with Water split into ${\text{Cu}}^{\text{2+}}$ and ${\text{SO}}_{\text{4}}{}^{\text{2-}}$

Interpretation Introduction

Interpretation: The equations for the following strong electrolytes have to be written.

Concept Introduction:

A strong electrolyte totally dissociates in a solution. These ions are good conductors of emotional current in the solution.

Answer to Problem 16SR

${\text{NaOH}}_{\left(\text{s}\right)}\to {\text{Na}}^{\text{+}}{}_{\left(\text{aq}\right)}{\text{+OH}}^{\text{-}}{}_{\left(\text{aq}\right)}$

Explanation of Solution

To write the dissociation equation of $\text{NaOH}$

The dissociation equation of $\text{NaOH}$ is given as,

${\text{NaOH}}_{\left(\text{s}\right)}\to {\text{Na}}^{\text{+}}{}_{\left(\text{aq}\right)}{\text{+OH}}^{\text{-}}{}_{\left(\text{aq}\right)}$

Sodium hydroxide on dissolving with Water split into ${\text{Na}}^{\text{+}}$ and ${\text{OH}}^{\text{-}}$