Chapter 10, Problem 153AP

Interpretation Introduction

Interpretation:

The mass of oxygen gas present in cylinder at given pressure and temperatureand volume(in L) of oxygengasproduced at $1.00\text{ atm}$, $22°\text{C}$ are to be calculated.

Concept introduction:

The standard form of theideal gas equation is as follows:

$PV=nRT$

Here, $P$ is the pressure, $V$ is the volume, $n$ is the number of moles, $R$ is gas constant, and $T$ is the temperature.

The number of moles is the ratio of mass to the molar mass.

$n=\frac{m}{M}$

Here, $n$ is the number of moles, $m$ is the mass, and $M$ is the molar mass.

The conversion of temperature from degree Celsius to kelvin can be done by using the formula given below:

$T\left(\text{K}\right)=T\left(°\text{C}\right)+273.15$