Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access)
Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access)
7th Edition
ISBN: 9781319125882
Author: David L. Nelson, Michael M. Cox
Publisher: W. H. Freeman
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Chapter 10, Problem 13P
Summary Introduction

To determine: The cleavage products of PIP2 by phospholipase C.

Introduction: Phosphatidylinositol 4,5-bisphosphate ( PIP2 ) is an essential lipid that is integral to the plasma membrane of the plant and animal cells. It works as a second messenger in a various signaling pathways and also involved in metabolic processes. PIP2 is an important phosphoinositide that makes about 1% of the cell membrane. PIP2 is also involved in the signaling transduction of the extracellular or intracellular components.

Summary Introduction

To compare: The DAG and IP3 with respect to their properties and solubilities in water.

Introduction: DAG and IP3 are the products of the hydrolysis of PIP2 by the enzyme phospholipase C. DAG pathway is a signaling transduction pathway that is involved in the activation of enzymes. IP3 molecule is the negatively charges polar molecule. IP3 involved in the signaling transduction of chemicals such as growth factors, hormones, and neurotransmitters.

Summary Introduction

To predict: Whether either would diffuse readily through the cytosol.

Introduction: DAG and IP3 are the products of the hydrolysis of PIP2 by the enzyme phospholipase C. DAG pathway is a signaling transduction pathway that is involved in the activation of enzymes. IP3 molecule is the negatively charges polar molecule. IP3 involved in the signaling transduction of chemicals such as growth factors, hormones, and neurotransmitters.

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need help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).   Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%.   Part B - Compare difference in free energy to the thermal energy Divide the…
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