The boiling point and freezing point has to be calculated. Concept Introduction: The depression in freezing point, the elevation of boiling point and osmotic pressure are together known as colligative properties. The elevation in boiling point can be given by the equation, ΔT=K b m solute Where, ΔT = change in boiling point elevation K b = molal boiling point elevation constant m solute = molality of solute The depression in freezing point can be given by the equation, ΔT=K f m solute Where, ΔT =change in freezing point depression K f = molal freezing point depression constant m solute = molality of solute
The boiling point and freezing point has to be calculated. Concept Introduction: The depression in freezing point, the elevation of boiling point and osmotic pressure are together known as colligative properties. The elevation in boiling point can be given by the equation, ΔT=K b m solute Where, ΔT = change in boiling point elevation K b = molal boiling point elevation constant m solute = molality of solute The depression in freezing point can be given by the equation, ΔT=K f m solute Where, ΔT =change in freezing point depression K f = molal freezing point depression constant m solute = molality of solute
Solution Summary: The author explains that the boiling point and the freezing point are together known as colligative properties. The molarity of ionized Formic acid solution is calculated by the equation.
Interpretation: The boiling point and freezing point has to be calculated.
Concept Introduction: The depression in freezing point, the elevation of boiling point and osmotic pressure are together known as colligative properties.
The elevation in boiling point can be given by the equation,
ΔT=Kbmsolute
Where,
ΔT= change in boiling point elevation
Kb = molal boiling point elevation constant
msolute = molality of solute
The depression in freezing point can be given by the equation,
Indicate whether the product of the reaction between Naphthalene and CrO3 in acetic acid at 25ºC is 1,4 naphthoquinone or phthalic anhydride.
Indicate the products of the reaction between CH3COCH2COOC2H5 and Na+-OC2H5.
Primary, Secondary, and
Tertiary Alcohols
O-H
O-H
O-H
R₁-C-H
R₁-C-H
R₁-C-R₁
H
R₂
R₂
Primary
Alcohol
Secondary
Alcohol
ChemistryLearner.com
R stands for Carbon group like ethyl methyl propyl
Tertiary
Alcohol
If 1 carbon group with two H attached to alcoholic carbon, then primary
If 2 carbon group and 1 H are attached to alcoholic carbon, then secondary
IF 3 carbon group and no H attach to alcoholic carbon then tertiary.
The bottom line
Starting
"Weak" oxidant
material
PCC, DMP, Swern, etc
Primary alcohol
Aldehyde
OH
Secondary alcohol
Ketone
OH
"Strong" oxidant
KMnO4, H₂CrO4
(or equivalent)
OH
Carboxylic acid
요
Ketone
No reaction
No reaction
Tertiary alcohol
1. Is ethanol a primary, secondary, or tertiary alcohol? Write out the
structures of
ethanol and any oxidation products of ethanol. If there is more than one
oxidation product, give the structure of each of the products.
2. Is 2-propanol a primary, secondary, or tertiary alcohol? Write out the
structures of
2-propanol and any…
Chapter 10 Solutions
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