Chapter 10, Problem 124CP

(a)

Interpretation Introduction

Interpretation: The molar mass and improvisation in the results has to be calculated.

Concept Introduction:

Molar mass of a compound can be given by mass of a substance to the amount of the substance. It can be given by expression,

$\text{Molar}\text{mass}\text{=}\frac{\text{Mass}\text{of}\text{substance}}{\text{Amount}\text{of}\text{substance}}$

The depression in freezing point, the elevation of boiling point and osmotic pressure are together known as colligative properties.

The depression in freezing point can be given by the equation,

${\text{ΔT=K}}_{\text{f}}{\text{m}}_{\text{solute}}$

 Where, $\text{ΔT}$=change in freezing point depression

                         ${\text{K}}_{\text{f}}$= molal freezing point depression constant

                                                ${\text{m}}_{\text{solute}}$ = molality of solute

(b)

Interpretation Introduction

Interpretation: The molar mass and improvisation in the results has to be calculated.

Concept Introduction:

Molar mass of a compound can be given by mass of a substance to the amount of the substance. It can be given by expression,

$\text{Molar}\text{mass}\text{=}\frac{\text{Mass}\text{of}\text{substance}}{\text{Amount}\text{of}\text{substance}}$

The depression in freezing point, the elevation of boiling point and osmotic pressure are together known as colligative properties.

The depression in freezing point can be given by the equation,

${\text{ΔT=K}}_{\text{f}}{\text{m}}_{\text{solute}}$

 Where, $\text{ΔT}$=change in freezing point depression

                         ${\text{K}}_{\text{f}}$= molal freezing point depression constant

                                                ${\text{m}}_{\text{solute}}$ = molality of solute

(c)

Interpretation Introduction

Interpretation: The molar mass and improvisation in the results has to be calculated.

Concept Introduction:

Molar mass of a compound can be given by mass of a substance to the amount of the substance. It can be given by expression,

$\text{Molar}\text{mass}\text{=}\frac{\text{Mass}\text{of}\text{substance}}{\text{Amount}\text{of}\text{substance}}$

The depression in freezing point, the elevation of boiling point and osmotic pressure are together known as colligative properties.

The depression in freezing point can be given by the equation,

${\text{ΔT=K}}_{\text{f}}{\text{m}}_{\text{solute}}$

 Where, $\text{ΔT}$=change in freezing point depression

                         ${\text{K}}_{\text{f}}$= molal freezing point depression constant

                                                ${\text{m}}_{\text{solute}}$ = molality of solute