5th Edition

ISBN: 8220103026918

Author: Walker

Publisher: PEARSON

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Textbook Question

Chapter 10, Problem 11PCE

The angle an airplane propeller makes with the horizontal as a function of time is given by θ = (125rad/s)t + (42.5rad/s²)t². (a) Estimate the instantaneous angular velocity at t = 0.00 by calculating the average angular velocity from t = 0.00 to t = 0.010s. (b) Estimate the instantaneous angular velocity at t = 1.000 s by calculating the average angular velocity from t = 1.000 s to t = 1.010 s. (c) Estimate the instantaneous angular velocity at t = 2.000 s by calculating the average angular velocity from t = 2.000s to t = 2.010s. (d) Based on your results from parts (a), (b), and (c), is the angular acceleration of the propeller positive, negative or zero? Explain, (e) Calculate the average angular acceleration from t = 0.00 to t = 1.00s and from t = 1.00s to t = 2.00 s.

Definition Definition Rate of change of angular velocity. Angular acceleration indicates how fast the angular velocity changes over time. It is a vector quantity and has both magnitude and direction. Magnitude is represented by the length of the vector and direction is represented by the right-hand thumb rule. An angular acceleration vector will be always perpendicular to the plane of rotation. Angular acceleration is generally denoted by the Greek letter α and its SI unit is rad/s 2 .

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Chapter 10, Problem 10PCE

Chapter 10, Problem 12PCE

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Example Two charges, one with +10 μC of charge, and another with - 7.0 μC of charge are placed in line with each other and held at a fixed distance of 0.45 m. Where can you put a 3rd charge of +5 μC, so that the net force on the 3rd charge is zero?

* Coulomb's Law Example Three charges are positioned as seen below. Charge 1 is +2.0 μC and charge 2 is +8.0μC, and charge 3 is - 6.0MC. What is the magnitude and the direction of the force on charge 2 due to charges 1 and 3? 93 kq92 F == 2 r13 = 0.090m 91 r12 = 0.12m 92 Coulomb's Constant: k = 8.99x10+9 Nm²/C² ✓

Make sure to draw a Free Body Diagram as well

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