Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN: 9781285199047
Author: John W. Moore, Conrad L. Stanitski
Publisher: Cengage Learning
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Chapter 10, Problem 115QRT

(a)

Interpretation Introduction

Interpretation:

The given blanks have to be filled with suitable words.

Concept Introduction:

The fatty acid can react with glycerol to form triglyceride with the formation of ester linkages.  The reaction between acid and alcohol gives an ester as a major product.  The ester group is derived by a carboxylic acid group in which the acidic hydrogen is replaced by an alkyl group.

(a)

Expert Solution
Check Mark

Explanation of Solution

The given blank is: A triglyceride _______

The triglyceride is formed by the reaction of glycerol and fatty acids.  It is characterized by the presence of ester linkages. Box C contains a triglyceride.

Thus, A triglyceride Box C.

(b)

Interpretation Introduction

Interpretation:

The given blanks have to be filled with suitable words.

Concept Introduction:

Oxidation of alcohol is the process in which the hydroxyl group of alcohol gets transformed either into carboxyl group or into an aldehyde or to ketone.  Product obtained may depend on the oxidising agent used.  Therefore, in presence of mild oxidising agent, one gets aldehyde or ketone.

(b)

Expert Solution
Check Mark

Explanation of Solution

The given blank is: Final oxidation product of a primary alcohol Box G.

Oxidation of alcohol is the process in which the hydroxyl group of alcohol gets transformed either into carboxyl group or into an aldehyde or to ketone.  Product obtained may depend on the oxidising agent used.  Therefore, in presence of mild oxidising agent, one gets aldehyde or ketone.  In the presence of strong oxidizing agent, carboxylic acid is obtained.

Thus, final oxidation product of a primary alcohol Box G.

(c)

Interpretation Introduction

Interpretation:

The given blanks have to be filled with suitable words.

Concept Introduction:

Polymers are the high molecular mass compounds.  The small monomers units joined together to form large molecule and this reaction is known as polymerization reaction.  When two small molecules condense together to form a polymer with elimination of water molecule, the reaction is known as condensation polymerization.

(c)

Expert Solution
Check Mark

Explanation of Solution

The given blank is: Condensation polymerization monomer _____.

Box G contains a compound in which two carboxylic groups are present. These two carboxylic groups can undergo condensation polymerization which is characterized by the loss of water molecule.

Thus, Condensation polymerization monomer Box G.

(d)

Interpretation Introduction

Interpretation:

The given blanks have to be filled with suitable words.

Concept Introduction:

Polymers are the high molecular mass compounds.  The small monomers units joined together to form large molecule, this reaction is known as polymerization reaction.  Addition polymerization is the polymerization in which monomer units are linked together with no side product formation.  Addition polymerization is given by the molecules which contains carbon-carbon double bond.

(d)

Expert Solution
Check Mark

Explanation of Solution

The given blank is: Segment of an addition polymer molecule _____.

Addition polymers are formed by the addition reaction of two monomer units.  There is no by product formed in addition polymerization reaction.  The given polymer is formed by the addition polymerization reaction of dichloroethene molecule.

Thus, Segment of an addition polymer molecule Box F.

(e)

Interpretation Introduction

Interpretation:

The given blanks have to be filled with suitable words.

Concept Introduction:

Oxidation of alcohol is the process in which the hydroxyl group of alcohol gets transformed either into an aldehyde or into ketone.  To get an aldehyde or ketone, oxidation of acohol must takes place in the presence of mild oxidising agent such as copper at Chemistry: The Molecular Science, Chapter 10, Problem 115QRT , additional homework tip  1.  Product obtained may be aldehyde or ketone. It depends on the nature of alcohol which may be primary, or secondary alcohol.

(e)

Expert Solution
Check Mark

Explanation of Solution

The given blank is: Initial oxidation product of a primary alcohol _____.

The initial oxidation of a primary alcohol results in the formation of an aldehyde. Compound in Box D is an aldehyde.

Thus, initial oxidation product of a primary alcohol Box D.

(f)

Interpretation Introduction

Interpretation:

The given blanks have to be filled with suitable words.

Concept Introduction:

An amide bond is formed between a carboxylic acid and an amine.  Peptide linkage is formed between two amino acids.  The carboxylic acid group of one amino acid reacts with an amino group of another amino acid to form an amide bond by removing a water molecule.

(f)

Expert Solution
Check Mark

Explanation of Solution

The given blank is: Contains an amide bond _____.

An amide bond is formed between a carboxylic acid and an amine.  The carboxylic acid group of one amino acid reacts with an amino group of another amino acid to form an amide bond by removing a water molecule.  Compound in Box B contains an amide bond.

Thus, Contains an amide bond Box B.

(g)

Interpretation Introduction

Interpretation:

The given blanks have to be filled with suitable words.

Concept Introduction:

Addition polymerization is the polymerization in which monomer units are linked together with no side product formation.  Addition polymerization is given by the molecules which contains carbon-carbon double bond.

(g)

Expert Solution
Check Mark

Explanation of Solution

The given blank is: Addition polymerization monomer _____.

Addition polymerization is given by the molecules which contains carbon-carbon double bond.  Compounds in Boxes A and H contain a double bond.

Thus, Addition polymerization monomers are Box A and Box H.

(h)

Interpretation Introduction

Interpretation:

The given blanks have to be filled with suitable words.

Concept Introduction:

The reaction between acid and alcohol gives an ester as a major product.  The ester is derived by a carboxylic acid group in which the acidic hydrogen is replaced by an alkyl group.

(h)

Expert Solution
Check Mark

Explanation of Solution

The given blank is: Contains an ester linkage _____.

The triglyceride is formed by the reaction of glycerol and fatty acids.  It is characterized by the presence of ester linkages. Box C contains a triglyceride.

Thus, contains an ester linkage Box C.

(i)

Interpretation Introduction

Interpretation:

The given blanks have to be filled with suitable words.

Concept Introduction:

Oxidation of alcohol is the process in which the hydroxyl group of alcohol gets transformed either into an aldehyde or into ketone.  To get an aldehyde or ketone, oxidation of acohol must takes place in the presence of mild oxidizing agent such as copper at Chemistry: The Molecular Science, Chapter 10, Problem 115QRT , additional homework tip  2.  Product obtained may be aldehyde or ketone. It depends on the nature of alcohol which may be primary, or secondary alcohol.

(i)

Expert Solution
Check Mark

Explanation of Solution

The given blank is: Final oxidation product of a secondary alcohol _____.

Oxidation of alcohol is the process in which the hydroxyl group of alcohol gets transformed either into an aldehyde or into ketone.  Secondary alcohols undergo oxidation to form ketons.  Compound in Box I is a ketone.

Thus, final oxidation product of a secondary alcohol is Box I.

(j)

Interpretation Introduction

Interpretation:

The given blanks have to be filled with suitable words.

Concept Introduction:

There are three types of alcohols: primary, secondary and tertiary.  The type of alcohols depends upon the carbon atom to which the hydroxyl group is attached.

(j)

Expert Solution
Check Mark

Explanation of Solution

The given blank is: A tertiary alcohol _____.

The compound given in Box E is a tertiary alcohol. The hydroxyl group is attached with a carbon atom that is attached with three other carbon atoms.

Thus, a tertiary alcohol Box E.

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Chapter 10 Solutions

Chemistry: The Molecular Science

Ch. 10.4 - Prob. 10.8CECh. 10.4 - Prob. 10.9CECh. 10.4 - Prob. 10.10CECh. 10.4 - Prob. 10.11ECh. 10.5 - Prob. 10.12ECh. 10.5 - Prob. 10.4PSPCh. 10.5 - Prob. 10.13ECh. 10.6 - Prob. 10.14CECh. 10.6 - Prob. 10.5PSPCh. 10.6 - Prob. 10.6PSPCh. 10.6 - Prob. 10.7PSPCh. 10.6 - Prob. 10.8PSPCh. 10.6 - Prob. 10.9PSPCh. 10.6 - Prob. 10.15CECh. 10.6 - Prob. 10.16ECh. 10.7 - Prob. 10.17CECh. 10.7 - Prob. 10.18CECh. 10.7 - Prob. 10.19CECh. 10.7 - Prob. 10.20CECh. 10.7 - Prob. 10.10PSPCh. 10.7 - Prob. 10.21ECh. 10 - Prob. ISPCh. 10 - Prob. IISPCh. 10 - Prob. IIISPCh. 10 - Prob. 1QRTCh. 10 - Prob. 2QRTCh. 10 - Prob. 3QRTCh. 10 - Prob. 4QRTCh. 10 - Prob. 5QRTCh. 10 - Prob. 6QRTCh. 10 - Prob. 7QRTCh. 10 - Give two reasons why ethylene glycol has a higher...Ch. 10 - Prob. 9QRTCh. 10 - Prob. 10QRTCh. 10 - Prob. 11QRTCh. 10 - Prob. 12QRTCh. 10 - Prob. 13QRTCh. 10 - Prob. 14QRTCh. 10 - Prob. 15QRTCh. 10 - Prob. 16QRTCh. 10 - Prob. 17QRTCh. 10 - Prob. 18QRTCh. 10 - Prob. 19QRTCh. 10 - Prob. 20QRTCh. 10 - Prob. 21QRTCh. 10 - Prob. 22QRTCh. 10 - Prob. 23QRTCh. 10 - Prob. 24QRTCh. 10 - Prob. 25QRTCh. 10 - Prob. 26QRTCh. 10 - Prob. 27QRTCh. 10 - Prob. 28QRTCh. 10 - Prob. 29QRTCh. 10 - Prob. 30QRTCh. 10 - Prob. 31QRTCh. 10 - Prob. 32QRTCh. 10 - Prob. 33QRTCh. 10 - Prob. 34QRTCh. 10 - Prob. 35QRTCh. 10 - Prob. 36QRTCh. 10 - Prob. 37QRTCh. 10 - Prob. 38QRTCh. 10 - Prob. 39QRTCh. 10 - Prob. 40QRTCh. 10 - Prob. 41QRTCh. 10 - Prob. 42QRTCh. 10 - Prob. 43QRTCh. 10 - Prob. 44QRTCh. 10 - Prob. 45QRTCh. 10 - Prob. 46QRTCh. 10 - Prob. 47QRTCh. 10 - Beeswax contains this compound: Identify what...Ch. 10 - Prob. 49QRTCh. 10 - Prob. 50QRTCh. 10 - Prob. 51QRTCh. 10 - Prob. 52QRTCh. 10 - Prob. 53QRTCh. 10 - Prob. 54QRTCh. 10 - Prob. 55QRTCh. 10 - Prob. 56QRTCh. 10 - Prob. 57QRTCh. 10 - Prob. 58QRTCh. 10 - Prob. 59QRTCh. 10 - Prob. 60QRTCh. 10 - Prob. 61QRTCh. 10 - Prob. 62QRTCh. 10 - Prob. 63QRTCh. 10 - Prob. 64QRTCh. 10 - Prob. 65QRTCh. 10 - Prob. 66QRTCh. 10 - Prob. 67QRTCh. 10 - Prob. 68QRTCh. 10 - Prob. 69QRTCh. 10 - Prob. 70QRTCh. 10 - Prob. 71QRTCh. 10 - Prob. 72QRTCh. 10 - Prob. 73QRTCh. 10 - Prob. 74QRTCh. 10 - Prob. 75QRTCh. 10 - Prob. 76QRTCh. 10 - Prob. 77QRTCh. 10 - Prob. 78QRTCh. 10 - Prob. 79QRTCh. 10 - Identify and name all the functional groups in...Ch. 10 - Prob. 81QRTCh. 10 - Prob. 82QRTCh. 10 - Prob. 83QRTCh. 10 - Prob. 84QRTCh. 10 - Prob. 85QRTCh. 10 - Prob. 86QRTCh. 10 - Prob. 87QRTCh. 10 - Prob. 88QRTCh. 10 - Prob. 89QRTCh. 10 - Prob. 90QRTCh. 10 - Prob. 91QRTCh. 10 - Prob. 92QRTCh. 10 - Prob. 93QRTCh. 10 - Prob. 94QRTCh. 10 - Prob. 95QRTCh. 10 - Prob. 96QRTCh. 10 - Assume that a car burns pure octane. C8H18 (d =...Ch. 10 - Prob. 98QRTCh. 10 - Prob. 99QRTCh. 10 - Prob. 100QRTCh. 10 - Prob. 101QRTCh. 10 - Prob. 102QRTCh. 10 - Prob. 103QRTCh. 10 - Prob. 104QRTCh. 10 - Prob. 105QRTCh. 10 - Prob. 106QRTCh. 10 - Prob. 107QRTCh. 10 - Prob. 108QRTCh. 10 - Prob. 109QRTCh. 10 - Prob. 110QRTCh. 10 - Prob. 111QRTCh. 10 - Prob. 112QRTCh. 10 - Prob. 113QRTCh. 10 - Prob. 114QRTCh. 10 - Prob. 115QRTCh. 10 - Prob. 116QRTCh. 10 - Prob. 118QRTCh. 10 - Prob. 119QRTCh. 10 - Prob. 120QRTCh. 10 - Prob. 121QRTCh. 10 - Prob. 122QRTCh. 10 - Prob. 123QRTCh. 10 - Prob. 124QRTCh. 10 - Prob. 125QRTCh. 10 - Prob. 126QRTCh. 10 - Prob. 127QRTCh. 10 - Prob. 10.ACPCh. 10 - Prob. 10.BCPCh. 10 - Prob. 10.CCP
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