Explanation Given: Radius of the cylinder r=10 cm Length of the cylinder h=20 cm Density of liquid nitrogen is 0.807 g/ml Volume of liquid nitrogen is 25 ml Initial pressure of air in the container =760 mmhg=1 atm Temperature of the container is 298 K Here, according to the given question 25 ml of liquid nitrogen is poured into the cylindrical container, so we will calculate the volume of the cylinder using the radius and length of the cylinder. Now, when 25 ml of liquid nitrogen is poured into the cylinder, it means the volume of 25 ml air moves out of the cylinder. Now, calculate the initial volume of the air at 760 mmhg pressure and 298 K temperature before the addition of liquid nitrogen. After that we will calculate the number of moles of air using the ideal gas equation. We will also calculate the number of moles of 25 ml of liquid nitrogen that is poured into the container. Now we can calculate the total moles of gas present in the container by adding the moles of liquid nitrogen and initial moles of air present. Now using ideal gas equation, we can calculate the pressure of the gas inside the container using the volume of the cylindertemperature, and total moles of gas present in the container. After that we will calculate the surface area of the cylinder using the length and radius. Finally we will calculate the total force inside the container. Formula used: Volume of the cylinder can be calculated using the formula V=Πr 2 h where, r=radius h=length Number of moles can be calculated using the ideal gas equation n= P V R T Where n=number of moles P=Pressure of the gas V=volume of the gas T=Temperature R=universal gas constant Mass can be calculated using the formula Mass=Density ×Volume Number of moles can also be calculated as Number of moles= M a s s o f s u b s tan c e M o l a r m a s s Pressure can be calculated using the ideal gas equation PV=nRT P= n R T V Surface area of the cylinder can be calculated using the formula A=2Πr 2+2Πrh Force can be calculated using the formula Force=pressure ×Area Calculation: Volume of the cylinder V=Πr 2 h V=3.14×(10 cm) 2 ×20 cm =6280cm3 Now 1 cm 3 =0.001 L 6280cm 3 =6.28 L=6280 ml Volume of the cylinder, V=6.28 L Now, 25 ml of liquid nitrogen is poured into the cylinder Therefore,Initial volume of the air present inside the cylinder = Volume of the cylinder - Volume of liquid nitrogen =6280 ml-25 ml =6255 ml 1000 ml=1 l 6255 ml=6.255 L Initial volume of air present =6.255 L Now, Number of moles of air initially present inside the cylinder at 760 mmhg (1 atm) pressure and 298 K temperature Universal gas constant is 0...

Modified Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Chemistry: Structure and Properties (2nd Edition)

2nd Edition

ISBN: 9780134565613

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 10, Problem 112E

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The total force on the interior of the container at 298 K

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Chapter 10, Problem 111E

Chapter 10, Problem 113E

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Modified Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Chemistry: Structure and Properties (2nd Edition)

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The total force on the interior of the container at 298 K

Solution Summary: The author calculates the total force on the interior of the container at 298 K using the ideal gas equation.

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To determine: The total force on the interior of the container at 298 K

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Chapter 10 Solutions

To determine:

The total force on the interior of the container at 298 K