Explanation Given: Volume of the gas in the balloon = 2.95 L Initial Pressure = 0.998 atm. Initial temperature = 25°C Final temperature = -196°C Formula Used Ideal Gas Equation, PV = nRT Calculation: As per the ideal gas equation PV=nRT Thus, the number of the moles of the gas in the balloon P × V R × T = 0 . 998 a t m × 2 . 95 L 0 . 08206 L × a t m m o l e × K × 298 K Now upon cooling the balloon to -196 0C in the submerged liquid nitrogen Temperature = -196°C→(-196+273)K⇒77K Now the volume of the gas will be calculated from ideal gas equation i...

Pearson eText for Chemistry: structures and Properties -- Instant Access (Pearson+)

2nd Edition

ISBN: 9780136951537

Author: Nivaldo Tro

Publisher: PEARSON+

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Chapter 10, Problem 108E

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To determine: the observed volume of the balloon compare to your calculated value.

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Chapter 10, Problem 107E

Chapter 10, Problem 109E

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Chapter 10 Solutions

Pearson eText for Chemistry: structures and Properties -- Instant Access (Pearson+)

Ch. 10 - Prob. 1E Ch. 10 - Prob. 2E Ch. 10 - Prob. 3E Ch. 10 - Prob. 4E Ch. 10 - Prob. 5E Ch. 10 - Prob. 6E Ch. 10 - Prob. 7E Ch. 10 - Prob. 8E Ch. 10 - Prob. 9E Ch. 10 - Prob. 10E

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the observed volume of the balloon compare to your calculated value.

Solution Summary: The author compares the observed volume of the balloon with the calculated value. The actual volume decreases to 0.61 L because the collisions amid molecule happen through less kinetic energy.

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To determine: the observed volume of the balloon compare to your calculated value.

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Chapter 10 Solutions