Explanation Given: Pressure of methane and ethane mixture = 0.53 atm Pressure of product gases = 2.2 atm Formula used: Partial pressure = pressure ( gas ) total pressure Calculation: The complete combustion equations will be CH 4 +2O 2 →CO 2 (g)+2H 2 O(g) C 2 H 6 3.5O 2 →2CO 2 (g)+3H 2 O(g) As volume and temperature are constant, the pressure will be directly proportional to moles of gases. Let initial pressure of methane gas = x atm Pressure of ethane gas = y Each moles of methane will give one moles of carbon dioxide and two moles of water, so its combustion will produce x atm of carbon dioxide and 2x atm of water...

Pearson eText for Chemistry: structures and Properties -- Instant Access (Pearson+)

2nd Edition

ISBN: 9780136951537

Author: Nivaldo Tro

Publisher: PEARSON+

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Question

Chapter 10, Problem 137E

Interpretation Introduction

To determine:

The mole fraction of CH₄ in the mixture of CH₄ and C₂H₅.

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Chapter 10, Problem 136E

Chapter 10, Problem 138E

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Pearson eText for Chemistry: structures and Properties -- Instant Access (Pearson+)

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