Concept explainers
Predict the geometries of the following species using the VSEPR method: (a) PCl3, (b) CHCl3, (c) SiH4, (d) TeCl4.
(a)
Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.
Concept Introduction:
Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).
VSEPR Theory:
As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,
- The first step is to draw the correct Lewis structure for the molecule.
- Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
- Finally, the geometry is predicted by using the orientation of atoms.
If the molecules () have two atoms bonded with the central atom then the molecular geometry by considering the orientation of atoms is linear if it has lone of electron over the central atom then the molecular geometry will be bent.
The molecules of type will have shape like trigonal planar and if the molecules has lone pairs then the molecular geometry will be tetrahedral.
The molecules of type will have shape like tetrahedral, and geometry of type will have trigonal bipyramidal and will have shape like octahedral respectively.
Lewis structure for any molecule is drawn by using the following steps,
First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined
The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.
Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.
Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.
Answer to Problem 10.7QP
(a)
Trigonal pyramidal
Explanation of Solution
To predict: The geometry for the given molecule.
Draw the Lewis structure for the molecule (a)
First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 26.
The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 6 has to be subtracted with 26 as each bond contains two electrons with it and there are three bonds in the skeletal structure.
Finally, the 20 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.
Determine the molecular geometry for the molecule (a) using VSEPR.
The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since theis bonded with three chlorine atoms and one lone pair of electron with it.
The molecular geometry for the given molecule is trigonal pyramidal due to the presence of one lone pair around the central atom.
(b)
Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.
Concept Introduction:
Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).
VSEPR Theory:
As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,
- The first step is to draw the correct Lewis structure for the molecule.
- Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
- Finally, the geometry is predicted by using the orientation of atoms.
If the molecules () have two atoms bonded with the central atom then the molecular geometry by considering the orientation of atoms is linear if it has lone of electron over the central atom then the molecular geometry will be bent.
The molecules of type will have shape like trigonal planar and if the molecules has lone pairs then the molecular geometry will be tetrahedral.
The molecules of type will have shape like tetrahedral, and geometry of type will have trigonal bipyramidal and will have shape like octahedral respectively.
Lewis structure for any molecule is drawn by using the following steps,
First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined
The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.
Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.
Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.
Answer to Problem 10.7QP
(b)
Tetrahedral
Explanation of Solution
To predict: The geometry for the given molecule.
Draw the Lewis structure for the molecule (b)
First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 26.
The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 26 as each bond contains two electrons with it and there are four bonds in the skeletal structure.
Finally, the 18 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.
Determine the molecular geometry for the molecule (b) using VSEPR.
The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral as there is no lone pair of electron over the central metal atom and hence the molecular geometry for the given molecule is also Tetrahedral.
(c)
Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.
Concept Introduction:
Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).
VSEPR Theory:
As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,
- The first step is to draw the correct Lewis structure for the molecule.
- Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
- Finally, the geometry is predicted by using the orientation of atoms.
If the molecules () have two atoms bonded with the central atom then the molecular geometry by considering the orientation of atoms is linear if it has lone of electron over the central atom then the molecular geometry will be bent.
The molecules of type will have shape like trigonal planar and if the molecules has lone pairs then the molecular geometry will be tetrahedral.
The molecules of type will have shape like tetrahedral, and geometry of type will have trigonal bipyramidal and will have shape like octahedral respectively.
Lewis structure for any molecule is drawn by using the following steps,
First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined
The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.
Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.
Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.
Answer to Problem 10.7QP
(c)
Tetrahedral
Explanation of Solution
To predict: The geometry for the given molecule.
Draw the Lewis structure for the molecule (c)
First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 8.
The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 8 as each bond contains two electrons with it and there are four bonds in the skeletal structure.
There are no remaining electrons hence all the atoms in the molecules are fulfilled the octet rule that is each atom involves in bonding in order to fill their valence with eight electrons.
Determine the molecular geometry for the molecule (c) using VSEPR.
The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since central atom does not contain any lone pair of electron with it.
The molecular geometry for the molecule is also tetrahedral as there are four atoms bonded with the central metal atom and there is absence of lone pair of electrons.
(d)
Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.
Concept Introduction:
Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).
VSEPR Theory:
As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,
- The first step is to draw the correct Lewis structure for the molecule.
- Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
- Finally, the geometry is predicted by using the orientation of atoms.
If the molecules () have two atoms bonded with the central atom then the molecular geometry by considering the orientation of atoms is linear if it has lone of electron over the central atom then the molecular geometry will be bent.
The molecules of type will have shape like trigonal planar and if the molecules has lone pairs then the molecular geometry will be tetrahedral.
The molecules of type will have shape like tetrahedral, and geometry of type will have trigonal bipyramidal and will have shape like octahedral respectively.
Lewis structure for any molecule is drawn by using the following steps,
First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined
The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.
Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.
Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.
Answer to Problem 10.7QP
(d)
See-saw shaped
Explanation of Solution
To predict: The geometry for the given molecule.
Draw the Lewis structure for the molecule (d)
First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 34.
The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 8 as each bond contains two electrons with it and there are four bonds in the skeletal structure.
Then the 26 electrons got after the subtractions should be placed over the atoms present in the molecule such that each atom contains eight electrons in the valence shell.
Determine the molecular geometry for the molecule (d) using VSEPR.
The electron domain for the given molecule is obtained by viewing the Lewis structure shows that it contains five electron domains since it has 4 chlorine atoms and one lone pair with it.
The molecular geometry for the molecule is see-saw shape due to the present of that one lone pair of electron.
Want to see more full solutions like this?
Chapter 10 Solutions
Chemistry
- Nonearrow_forwardIn the phase diagram of steel (two components Fe and C), region A is the gamma austenite solid and region B contains the gamma solid and liquid. Indicate the degrees of freedom that the fields A and B have,arrow_forwardFor a condensed binary system in equilibrium at constant pressure, indicate the maximum number of phases that can exist.arrow_forward
- Part V. Label ad match the carbons in compounds Jane and Diane w/ the corresponding peak no. in the Spectra (Note: use the given peak no. To label the carbons, other peak no are intentionally omitted) 7 4 2 -0.13 -0.12 -0.11 -0.10 -0.08 8 CI Jane 1 -0.09 5 210 200 190 180 170 160 150 140 130 120 110 100 -8 90 f1 (ppm) 11 8 172.4 172.0 f1 (ppr HO CI NH Diane 7 3 11 80 80 -80 -R 70 60 60 2 5 -8 50 40 8. 170 160 150 140 130 120 110 100 90 -0 80 70 20 f1 (ppm) 15 30 -20 20 -60 60 -0.07 -0.06 -0.05 -0.04 -0.03 -0.02 -0.01 -0.00 -0.01 10 -0.17 16 15 56 16 -0.16 -0.15 -0.14 -0.13 -0.12 -0.11 -0.10 -0.09 -0.08 -0.07 -0.06 -0.05 -0.04 17.8 17.6 17.4 17.2 17.0 f1 (ppm) -0.03 -0.02 550 106 40 30 20 20 -0.01 -0.00 F-0.01 10 0arrow_forwardConsider the reaction of 2-methylpropane with a halogen. With which halogen will the product be almost exclusively 2-halo-2-methylpropane? 1. F2 2. Cl2 3. Br2 4. I2arrow_forwardNonearrow_forward
- Nonearrow_forwardn Feb 3 A T + 4. (2 pts) Draw the structure of the major component of the Limonene isolated. Explain how you confirmed the structure. 5. (2 pts) Draw the fragment corresponding to the base peak in the Mass spectrum of Limonene. 6. (1 pts) Predict the 1H NMR spectral data of R-Limonene. Proton NMR: 5.3 pon multiplet (H Ringarrow_forwardPart VI. Ca H 10 O is the molecular formula of compound Tom and gives the in the table below. Give a possible structure for compound Tom. 13C Signals summarized C1 C2 C3 C4 C5 C6 C7 13C shift (ppm) 23.5 27.0 33.0 35.8 127 162 205 DEPT-90 + DEPT-135 + +arrow_forward
- 2. Using the following data to calculate the value of AvapH o of water at 298K. AvapH o of water at 373K is 40.7 kJ/mol; molar heat capacity of liquid water at constant pressure is 75.2J mol-1 K-1 and molar heat capacity of water vapor at constant pressure is 33.6 J mol-1 K-1.arrow_forwardPart VII. Below are the 'HNMR 13 3 C-NMR, COSY 2D- NMR, and HSQC 20-NMR (Similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H13 O. Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum ли 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8 f1 (ppm)arrow_forward3. Draw the expanded structural formula, the condensed structural formula, and the skeletal structural formula for 2-pentene. expanded structure: Condensed structure: Skeletal formula: 4. Draw the expanded structural formula, the condensed structural formula, and the skeletal structural formula for 2-methyl-3-heptene. expanded structure: Condensed structure: Skeletal formula: following structurearrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning