The mechanism of the formation of the product of the given reaction is to be drawn. Concept introduction: In an E2 reaction, a proton and a leaving group on adjacent carbons are lost, and a double bond is formed between the two carbons. In the case of alkynes , a proton present on the propargylic carbon can be removed under basic conditions. This step is reversible under the given conditions. A proton is then added to the terminal carbon via resonance stabilization and proton transfer step.

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Answer 1

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Chapter 10, Problem 10.70P

Interpretation Introduction

Interpretation:

The mechanism of the formation of the product of the given reaction is to be drawn.

Concept introduction:

In an E2 reaction, a proton and a leaving group on adjacent carbons are lost, and a double bond is formed between the two carbons.

In the case of alkynes, a proton present on the propargylic carbon can be removed under basic conditions. This step is reversible under the given conditions. A proton is then added to the terminal carbon via resonance stabilization and proton transfer step.

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CS2(g) →CS(g) + S(g) The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹. S What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?

CS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.

Answer 2

Question

Chapter 10, Problem 10.70P

Interpretation Introduction

Interpretation:

The mechanism of the formation of the product of the given reaction is to be drawn.

Concept introduction:

In an E2 reaction, a proton and a leaving group on adjacent carbons are lost, and a double bond is formed between the two carbons.

In the case of alkynes, a proton present on the propargylic carbon can be removed under basic conditions. This step is reversible under the given conditions. A proton is then added to the terminal carbon via resonance stabilization and proton transfer step.

Expert Solution & Answer

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Answer 3

Question

Chapter 10, Problem 10.70P

Interpretation Introduction

Interpretation:

The mechanism of the formation of the product of the given reaction is to be drawn.

Concept introduction:

In an E2 reaction, a proton and a leaving group on adjacent carbons are lost, and a double bond is formed between the two carbons.

In the case of alkynes, a proton present on the propargylic carbon can be removed under basic conditions. This step is reversible under the given conditions. A proton is then added to the terminal carbon via resonance stabilization and proton transfer step.

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Answer 4

Question

Chapter 10, Problem 10.70P

Interpretation Introduction

Interpretation:

The mechanism of the formation of the product of the given reaction is to be drawn.

Concept introduction:

In an E2 reaction, a proton and a leaving group on adjacent carbons are lost, and a double bond is formed between the two carbons.

In the case of alkynes, a proton present on the propargylic carbon can be removed under basic conditions. This step is reversible under the given conditions. A proton is then added to the terminal carbon via resonance stabilization and proton transfer step.

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Answer 5

Chapter 10, Problem 10.70P

Interpretation Introduction

Interpretation:

The mechanism of the formation of the product of the given reaction is to be drawn.

Concept introduction:

In an E2 reaction, a proton and a leaving group on adjacent carbons are lost, and a double bond is formed between the two carbons.

In the case of alkynes, a proton present on the propargylic carbon can be removed under basic conditions. This step is reversible under the given conditions. A proton is then added to the terminal carbon via resonance stabilization and proton transfer step.

Answer 6

Chapter 10, Problem 10.70P

Interpretation Introduction

Interpretation:

The mechanism of the formation of the product of the given reaction is to be drawn.

Concept introduction:

In an E2 reaction, a proton and a leaving group on adjacent carbons are lost, and a double bond is formed between the two carbons.

In the case of alkynes, a proton present on the propargylic carbon can be removed under basic conditions. This step is reversible under the given conditions. A proton is then added to the terminal carbon via resonance stabilization and proton transfer step.

Answer 7

Chapter 10, Problem 10.70P

Interpretation Introduction

Interpretation:

The mechanism of the formation of the product of the given reaction is to be drawn.

Concept introduction:

In an E2 reaction, a proton and a leaving group on adjacent carbons are lost, and a double bond is formed between the two carbons.

In the case of alkynes, a proton present on the propargylic carbon can be removed under basic conditions. This step is reversible under the given conditions. A proton is then added to the terminal carbon via resonance stabilization and proton transfer step.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 10 - Prob. 10.1P Ch. 10 - Prob. 10.2P Ch. 10 - Prob. 10.3P Ch. 10 - Prob. 10.4P Ch. 10 - Prob. 10.5P Ch. 10 - Prob. 10.6P Ch. 10 - Prob. 10.7P Ch. 10 - Prob. 10.8P Ch. 10 - Prob. 10.9P Ch. 10 - Prob. 10.10P

Solution Summary: The author explains the mechanism for the formation of the product of a given reaction based on its products and reaction conditions.

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