C++ How to Program (10th Edition)
C++ How to Program (10th Edition)
10th Edition
ISBN: 9780134448237
Author: Paul J. Deitel, Harvey Deitel
Publisher: PEARSON
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15. The only way to access data stored in heap memory is through pointer variables malloc () allocation tables а. b. С. d. a buffer memory
Segmentation: Select all of the following statements that are true. In segmentation, a logical address always has a length of 32 bit. In order to translate logical into physical addresses, the memory management unit uses the segment part of the logical address to determine the start address in the segment table and adds the offset to this to get the physical address. In segmentation, the logical address consists of a segment part and an offset. The segment length is limited by the maximum possible segment number. When applying segmentation, processes are only allowed to access the memory within their segments. Segments can be assigned access rights and privilege levels.
(JAVA)Almost a priority queue. Design a data structure that supports the followingoperations for almost a priority queue:(i) FindSecondSmallest() which returns the second smallest item in the data structure.(ii) Insert(x) which inserts item x to the data structure.(iii) DeleteSecondSmallest() which removes the second smallest item from the datastructure.Your data structure should implement the operation FindSecondSmallest() in O(1), andthe other two operations in O(log n), where n is the number of elements in the datastructure.Problem 4: Binomial heaps. Let H1 and H2 be two binomial heaps. We would like tomerge H1 and H2 to obtain the binomial heap H and also to find the minimum key in H.A standard approach would be to perform the following sequence of operationsH = Merge(H1, H2);m = Min(H).Alternatively, we may perform the following sequence of operationsm1 = Min(H1);m2 = Min(H2);m = min{m1, m2};H = Merge(H1, H2).
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