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Science Chemistry EBK GET READY FOR ORGANIC CHEMISTRY

Appropriate curved arrows are to be provided; the enolate anion is to be labelled, and the type of elementary step is to be recognized by writing “proton transfer” or “S N 2” below each reaction arrow. Concept introduction: When an aldehyde (RCH=O) or ketone (R2C=O) is treated with an alkyl halide alone, no reaction occurs. When a strong base like sodium hydride (NaH) or sodium amide (NaNH 2 ) is added first, however, alkylation can take place at the α carbon (i.e., at the C atom adjacent to the C=O group).

Appropriate curved arrows are to be provided; the enolate anion is to be labelled, and the type of elementary step is to be recognized by writing “proton transfer” or “S N 2” below each reaction arrow. Concept introduction: When an aldehyde (RCH=O) or ketone (R2C=O) is treated with an alkyl halide alone, no reaction occurs. When a strong base like sodium hydride (NaH) or sodium amide (NaNH 2 ) is added first, however, alkylation can take place at the α carbon (i.e., at the C atom adjacent to the C=O group).

Solution Summary: The author explains that alkylation of an aldehyde or ketone can be carried out using proton transfer.

EBK GET READY FOR ORGANIC CHEMISTRY

EBK GET READY FOR ORGANIC CHEMISTRY

2nd Edition

ISBN: 9780100576377

Author: KARTY

Publisher: YUZU

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Chapter 10, Problem 10.5YT

Interpretation Introduction

Interpretation:

Appropriate curved arrows are to be provided; the enolate anion is to be labelled, and the type of elementary step is to be recognized by writing “proton transfer” or “S_N2” below each reaction arrow.

Concept introduction:

When an aldehyde (RCH=O) or ketone (R2C=O) is treated with an alkyl halide alone, no reaction occurs. When a strong base like sodium hydride (NaH) or sodium amide (NaNH₂) is added first, however, alkylation can take place at the α carbon (i.e., at the C atom adjacent to the C=O group).

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Chapter 10, Problem 10.4YT

Chapter 10, Problem 10.6YT

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The initial rates method can be used to determine the rate law for a reaction. using the data for the reaction below, what is the rate law for reaction? A+B-C - ALA] At (mot Trial [A] (mol) (MD 2 1 0.075 [B]( 0.075 mo LS 01350 2 0.075 0.090 0.1944 3 0.090 0.075 0.1350 Report value of k with two significant Figure

Compare trials 1 and 2 where [B] is constant. The rate law can be written as: rate = k[A][B]". rate2 0.090 = 9. rate1 0.010 [A]m 6.0m = 3m [A] m 2.0m

Chapter 10 Solutions

EBK GET READY FOR ORGANIC CHEMISTRY

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