Pearson eText Organic Chemistry -- Instant Access (Pearson+)
Pearson eText Organic Chemistry -- Instant Access (Pearson+)
9th Edition
ISBN: 9780135213728
Author: Leroy Wade, Jan Simek
Publisher: PEARSON+
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Chapter 10, Problem 10.53SP

(a)

Interpretation Introduction

To determine: The reason corresponding to fact that given compound II has almost triple the molecular weight of compound I, but has a lower boiling point.

Interpretation: The reason corresponding to fact that given compound II has almost triple the molecular weight of compound I, but has a lower boiling point is to be explained.

Concept introduction: The boiling point of a liquid is defined as the temperature at which molecule in liquid phase has a vapour pressure equals to atmospheric pressure surrounding the liquid.

Hydrogen bonding is one of the major factors to that affect in the determination of the higher or lower boiling point of the compounds.

(b)

Interpretation Introduction

To determine: The reason corresponding to fact that dipole moment of compound II is much lower than a dipole moment of compound II being the presence of the six electronegative fluorine atoms.

Interpretation: The reason corresponding to fact that dipole moment of compound II is much lower than a dipole moment of compound II being the presence of the six electronegative fluorine atoms is to be explained.

Concept introduction: Dipole moment is defined as measure to check the polarity of the compounds. In polar molecules there is a large dipole moment is present.

Polar molecules like CCl4 and H2O.

(c)

Interpretation Introduction

To determine: The reason corresponding to fact that compound II is stronger acid than compound I.

Interpretation: The reason corresponding to fact that compound II is stronger acid than compound I is to be stated.

Concept introduction: The acidity of the compounds is determined on the basis of pKa value. The compounds which have less pKa value are more acidic in nature and compounds which have more pKa value are least acidic in nature.

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Chapter 10 Solutions

Pearson eText Organic Chemistry -- Instant Access (Pearson+)

Ch. 10.8B - Prob. 10.11PCh. 10.8B - Prob. 10.12PCh. 10.9A - Prob. 10.13PCh. 10.9B - Prob. 10.14PCh. 10.9C - Show how you would synthesize each tertiary...Ch. 10.9D - Prob. 10.16PCh. 10.9D - Show how you would add Grignard reagents to acid...Ch. 10.9D - A formate ester, such as ethyl formate, reacts...Ch. 10.9E - Prob. 10.19PCh. 10.9E - In Section9-7B, we saw how acetylide ions add to...Ch. 10.9F - Prob. 10.21PCh. 10.10A - Prob. 10.22PCh. 10.10B - Prob. 10.23PCh. 10.11B - Predict the products you would expect from the...Ch. 10.11B - Prob. 10.25PCh. 10.11B - Prob. 10.26PCh. 10.12 - Prob. 10.27PCh. 10.12 - Prob. 10.28PCh. 10.12 - Authentic skunk spray has become valuable for use...Ch. 10 - Give a systematic (IUPAC) name for each alcohol....Ch. 10 - Give systematic (IUPAC) names for the following...Ch. 10 - Draw the structures of the following compounds...Ch. 10 - Predict which member of each pair has the higher...Ch. 10 - Predict which member of each pair is more acidic,...Ch. 10 - Predict which member of each group is most soluble...Ch. 10 - Draw the organic products you would expect to...Ch. 10 - Prob. 10.37SPCh. 10 - Show how you would synthesize the following...Ch. 10 - Show how you would use Grignard syntheses to...Ch. 10 - Show how you would accomplish the following...Ch. 10 - Show how you would synthesize the following: a....Ch. 10 - Complete the following acid-base reactions. In...Ch. 10 - Prob. 10.43SPCh. 10 - Prob. 10.44SPCh. 10 - Geminal diols, or 1,1-diols, are usually unstable,...Ch. 10 - Vinyl alcohols are generally unstable, quickly...Ch. 10 - Compound A (C7H11Br) is treated with magnesium in...Ch. 10 - Prob. 10.48SPCh. 10 - Prob. 10.49SPCh. 10 - Prob. 10.50SPCh. 10 - Prob. 10.51SPCh. 10 - Prob. 10.52SPCh. 10 - Prob. 10.53SPCh. 10 - Prob. 10.54SPCh. 10 - Prob. 10.55SPCh. 10 - Prob. 10.56SPCh. 10 - Show how this 1 alcohol can be made from the...Ch. 10 - Prob. 10.58SPCh. 10 - Prob. 10.59SPCh. 10 - Prob. 10.60SP
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