
(a)
Interpretation: The compound that is likely to be more soluble in among the given pair is to be predicted.
Concept introduction: The polarity of solute and solvent determines the solubility solution. Solute and solvent of same polarity are soluble with each other and insoluble if polarity is different.
To determine: The compound that is likely to be more soluble in among the given pair.
(a)

Answer to Problem 10.48QP
Solution
The solubility of in
is more than that of
.
Explanation of Solution
Explanation
The dipole moment of the given compound is important for its solubility in . The dipole moment of
is zero and it solubilizes only non-polar compounds.
is a non-polar compound whereas
is a polar compound. Therefore,
is more soluble in
than
.
(b)
To determine: The compound that is likely to be more soluble in among the given pair.
(b)

Answer to Problem 10.48QP
Solution
The solubility of in
is more than that of
.
Explanation of Solution
Explanation
The polarity of ethanol in comparison to acetone is more because in ethanol, oxygen is attached to one carbon atom, whereas in acetone it lies between two carbon atoms and they cancel out each other.
Therefore, acetone being less polar solubilizes more in than ethanol.
(c)
To determine: The compound that is likely to be more soluble in among the given pair.
(c)

Answer to Problem 10.48QP
Solution
The solubility of in
is more than that of
.
Explanation of Solution
Explanation
The given compound is ionic compound and
is a non-ionic compound.
Ionic compounds are polar in nature and solubilize in polar solvent.
Therefore, being non-polar compound solubilizes more in
than
.
(d)
To determine: The compound that is likely to be more soluble in among the given pair.
(d)

Answer to Problem 10.48QP
Solution
The solubility of in
is more than that of
.
Explanation of Solution
Explanation
The given compounds are and
. Iodine is non-polar compound as its dipole moment is zero whereas
is ionic molecule and polar in nature. Therefore,
being non-polar compound solubilizes more in
than
.
Conclusion
- a. The solubility of
in
is more than that of
.
- b. The solubility of
in
is more than that of
.
- c. The solubility of
in
is more than that of
.
- d. The solubility of
in
is more than that of
.
Want to see more full solutions like this?
Chapter 10 Solutions
Chemistry: The Science in Context (Fourth Edition)
- Show how to convert ethyl benzene to (a) 2,5-dichlorobenzoic acid and (b) 2,4-dichlorobenzoic acid.arrow_forwardHelp me solve this problem. Thank you in advance.arrow_forward22.7 Predict the monoalkylated products of the following reactions with benzene. (a) AlCl3 Ya (b) AlCl3 (c) H3PO4 (d) 22.8 Think-Pair-Share AICI3 The reaction below is a common electrophilic aromatic substitution. SO3 H₂SO4 SO₂H (a) Draw the reaction mechanism for this reaction using HSO,+ as the electrophile. (b) Sketch the reaction coordinate diagram, where the product is lower in energy than the starting reactant. (c) Which step in the reaction mechanism is highest in energy? Explain. (d) Which of the following reaction conditions could be used in an electrophilic aro- matic substitution with benzene to provide substituted phenyl derivatives? (i) AICI3 HNO3 H₂SO4 K2Cr2O7 (iii) H₂SO4 (iv) H₂PO₁arrow_forward
- Is an acid-base reaction the only type of reaction that would cause leavening products to rise?arrow_forwardHelp me understand this! Thank you in advance.arrow_forward22.22 For each compound, indicate which group on the ring is more strongly activating and then draw a structural formula of the major product formed by nitration of the compound. Br CHO (a) CH3 (b) (c) CHO CH3 SO₂H (d) ☑ OCHS NO₂ (e) (f) CO₂H NHCOCH3 NHCOCH, (h) CHS 22.23 The following molecules each contain two aromatic rings. (b) 000-100- H3C (a) (c) Which ring in each undergoes electrophilic aromatic substitution more readily? Draw the major product formed on nitration.arrow_forward
- V Consider this step in a radical reaction: Br: ? What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. ⚫ionization termination initialization neutralization none of the abc Explanation Check 80 Ο F3 F1 F2 2 F4 01 % do5 $ 94 #3 X 5 C MacBook Air 25 F5 F6 66 ©2025 ˇ F7 29 & 7 8arrow_forwardShow how to convert ethyl benzene to (a) 2,5-dichlorobenzoic acid and (b) 2,4-dichlorobenzoic acid.arrow_forwardno aiarrow_forward
- Polymers may be composed of thousands of monomers. Draw three repeat units (trimer) of the polymer formed in this reaction. Assume there are hydrogen atoms there are hydrogen atoms on the two ends of the trimer. Ignore inorganic byproducts.arrow_forwardDraw a tetramer if this alternating copolymer pleasearrow_forwardDraw the monomers required to synthesize this condensation polymer.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





