The strength of Hydrogen bonding associated by O-H and N-H bonds has to be compared. Concept Introduction: Physical properties of ethers: Ethers are polar molecules in which Oxygen bears a partial negative charge and each attached to carbon bears a partial positive charge. Only weak dipole-dipole interactions exist between ether molecules in the liquid form. As ethers do not form hydrogen bonding are less soluble in water. Due to the presence of lone pairs on oxygen atom can act as hydrogen bond acceptors that makes them more water-soluble than hydrocarbons of comparable molecular weight. Hydrogen bonding: The attractive interactions between hydrogen atom bonded to an atom of high electronegativity (most commonly O or N) and a lone pair of electrons on another atom of electrons on another atom of high electronegativity (again, most commonly O or N). Boiling point: The temperature at which a liquid boils and turns into gas phase is known as boiling point.

Question

Want to see the full answer?

Answer 1

Question

Chapter 10, Problem 10.48P

(a)

Interpretation Introduction

Interpretation:

The strength of Hydrogen bonding associated by O-H and N-H bonds has to be compared.

Concept Introduction:

Physical properties of ethers: Ethers are polar molecules in which Oxygen bears a partial negative charge and each attached to carbon bears a partial positive charge. Only weak dipole-dipole interactions exist between ether molecules in the liquid form. As ethers do not form hydrogen bonding are less soluble in water. Due to the presence of lone pairs on oxygen atom can act as hydrogen bond acceptors that makes them more water-soluble than hydrocarbons of comparable molecular weight.

Hydrogen bonding: The attractive interactions between hydrogen atom bonded to an atom of high electronegativity (most commonly O or N) and a lone pair of electrons on another atom of electrons on another atom of high electronegativity (again, most commonly O or N).

Boiling point: The temperature at which a liquid boils and turns into gas phase is known as boiling point.

(b)

Interpretation Introduction

Interpretation:

The boiling pointof the compounds associated by O-H and N-H bonds has to be compared.

Concept Introduction:

Physical properties of ethers: Ethers are polar molecules in which Oxygen bears a partial negative charge and each attached to carbon bears a partial positive charge. Only weak dipole-dipole interactions exist between ether molecules in the liquid form. As ethers do not form hydrogen bonding are less soluble in water. Due to the presence of lone pairs on oxygen atom can act as hydrogen bond acceptors that makes them more water-soluble than hydrocarbons of comparable molecular weight.

Hydrogen bonding: The attractive interactions between hydrogen atom bonded to an atom of high electronegativity (most commonly O or N) and a lone pair of electrons on another atom of electrons on another atom of high electronegativity (again, most commonly O or N).

Boiling point: The temperature at which a liquid boils and turns into gas phase is known as boiling point.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

-AG|F=2E|V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: Acidic solution -0.93 +0.38 -0.51 -0.06 H3PO4 →H4P206 H3PO3 H3PO2 → P→ PH3 -0.28 -0.50 → -0.50 Basic solution 3-1.12 -1.57 -2.05 -0.89 PO HPO →→H2PO2 P PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P2O6 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH, 0.0 -0.5- 2 3 9 3 -1.5 -2.0 Pa H,PO H,PO H,PO -3 -1 0 2 4 Oxidation state, N 2 b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) c) Elemental phosphorus tends to disproportionate under basic conditions. Use data in…

These two reactions appear to start with the same starting materials but result in different products. How do the chemicals know which product to form? Are both products formed, or is there some information missing that will direct them a particular way?

What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 1 2 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Priva ×