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Concept explainers
(a)
Interpretation: The structure of stereoisomer that has higher melting point than eleostearic acid is to be drawn.
Concept introduction: Fatty acids are of two types: saturated fatty acid and unsaturated fatty acid. In Saturated fatty acid, double bond is absent, whereas unsaturated fatty acid consists of one or more than one double bond. The melting point of a fatty acid indirectly depends upon the number of double bond present in an acid. Higher is the number of double bonds in acid, lower will be the melting point of an acid.
When two higher priority groups are present on the opposite side then it is an
(b)
Interpretation: The structure of stereoisomer that has lower melting point is to be drawn.
Concept introduction: Fatty acids are of two types: saturated fatty acid and unsaturated fatty acid. In Saturated fatty acid, double bond is absent, whereas unsaturated fatty acid consists of one or more than one double bond. The melting point of a fatty acid indirectly depends upon the number of double bond present in an acid. Higher is the number of double bonds in acid, lower will be the melting point of an acid.
When two higher priority groups are present on the opposite side, then it is an
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Chapter 10 Solutions
ORGANIC CHEMISTRY
- true or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 5. 4NO2(g) ⇔ 2N2O4(g)arrow_forwardtrue or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 0.4. 2N2O4(g) ⇔ 4NO2(g)arrow_forwardtrue or false Using the following equilibrium, if heat is added the equilibrium will shift toward the reactants. N2(g) + 3H2(g) ⇔ 2NH3(g) + heatarrow_forward
- True or False Using the following equilibrium, if heat is added the equilibrium will shift toward the products. N2O4(g) + heat ⇔ 2NO2(g)arrow_forwardtrue or false Using the following equilibrium, if solid carbon is added the equilibrium will shift toward the products. C(s) + CO2(g) ⇔ 2CO(g)arrow_forwardProvide the complete mechanism for the reaction below. You must include appropriate arrows,intermediates, and formal charges. Please also provide a reason to explain why the 1,4-adduct is preferred over the 1,3-adduct.arrow_forward
- Which of the following pairs are resonance structures of one another? I. III. || III IV + II. :0: n P !༠ IV. EN: Narrow_forwardPredict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reactions.arrow_forwardA 8.25 g sample of aluminum at 55°C released 2500 J of heat. The specific heat of aluminum is 0.900 J/g°C. The density of aluminum is 2.70 g/mL. Calculate the final temperature of the aluminum sample in °C.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
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