Chemistry
Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Chapter 10, Problem 10.23QP
Interpretation Introduction

Interpretation: The reason corresponding to the fact that the melting point of Chemistry, Chapter 10, Problem 10.23QP , additional homework tip  1 is higher than methane, Chemistry, Chapter 10, Problem 10.23QP , additional homework tip  2 is to be stated.

Concept introduction: The intermolecular interaction between non-polar or least polar molecules is known as dispersion force. This is also known as, London force in honor of the Fritz London’s great work on it. Melting point of a compound is defined as the temperature at which the compounds start melt. At this temperature the bonds present within the molecules start weakens and hence, solid converts to the liquid form.

To determine: The reason corresponding to the fact that the melting point of Chemistry, Chapter 10, Problem 10.23QP , additional homework tip  3 is higher than methane, Chemistry, Chapter 10, Problem 10.23QP , additional homework tip  4.

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Chapter 10 Solutions

Chemistry

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