Fluid Mechanics
Fluid Mechanics
8th Edition
ISBN: 9780073398273
Author: Frank M. White
Publisher: McGraw-Hill Education
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Chapter 10, Problem 10.20P

An unfinished concrete sewer pipe, of diameter 4 ft, is flowing half-full at 39,500 U.S. gallons per minute. If this is the normal depth, what is the pipe slope, in degrees?

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Problem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/s
Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4
Problem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…

Chapter 10 Solutions

Fluid Mechanics

Ch. 10 - Prob. 10.11PCh. 10 - Prob. 10.12PCh. 10 - Prob. 10.13PCh. 10 - Prob. 10.14PCh. 10 - Prob. 10.15PCh. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Prob. 10.18PCh. 10 - Prob. 10.19PCh. 10 - An unfinished concrete sewer pipe, of diameter 4...Ch. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - Prob. 10.23PCh. 10 - Prob. 10.24PCh. 10 - Prob. 10.25PCh. 10 - Prob. 10.26PCh. 10 - Prob. 10.27PCh. 10 - Prob. 10.28PCh. 10 - Prob. 10.29PCh. 10 - Prob. 10.30PCh. 10 - Prob. 10.31PCh. 10 - Prob. 10.32PCh. 10 - Prob. 10.33PCh. 10 - Prob. 10.34PCh. 10 - Prob. 10.35PCh. 10 - Prob. 10.36PCh. 10 - Prob. 10.37PCh. 10 - Prob. 10.38PCh. 10 - Pl0.39 A trapezoidal channel has n = 0.022 and Sn...Ch. 10 - Prob. 10.40PCh. 10 - Prob. 10.41PCh. 10 - Prob. 10.42PCh. 10 - Prob. 10.43PCh. 10 - Prob. 10.44PCh. 10 - Prob. 10.45PCh. 10 - Prob. 10.46PCh. 10 - Prob. 10.47PCh. 10 - Prob. 10.48PCh. 10 - Prob. 10.49PCh. 10 - Prob. 10.50PCh. 10 - Prob. 10.51PCh. 10 - Prob. 10.52PCh. 10 - Prob. 10.53PCh. 10 - A clay tile V-shaped channel has an included angle...Ch. 10 - Prob. 10.55PCh. 10 - Prob. 10.56PCh. 10 - Prob. 10.57PCh. 10 - Prob. 10.58PCh. 10 - Prob. 10.59PCh. 10 - Prob. 10.60PCh. 10 - P10.59 Uniform water flow in a wide brick channel...Ch. 10 - P10.62 Consider the flow in a wide channel over a...Ch. 10 - Prob. 10.63PCh. 10 - Prob. 10.64PCh. 10 - Prob. 10.65PCh. 10 - Prob. 10.66PCh. 10 - Prob. 10.67PCh. 10 - Prob. 10.68PCh. 10 - Given is the flow of a channel of large width b...Ch. 10 - Prob. 10.70PCh. 10 - Prob. 10.71PCh. 10 - Prob. 10.72PCh. 10 - Prob. 10.73PCh. 10 - Prob. 10.74PCh. 10 - Prob. 10.75PCh. 10 - Prob. 10.76PCh. 10 - Prob. 10.77PCh. 10 - Prob. 10.78PCh. 10 - Prob. 10.79PCh. 10 - Prob. 10.80PCh. 10 - Prob. 10.81PCh. 10 - Prob. 10.82PCh. 10 - Prob. 10.83PCh. 10 - Prob. 10.84PCh. 10 - Pl0.85 The analogy between a hydraulic jump and a...Ch. 10 - Prob. 10.86PCh. 10 - Prob. 10.87PCh. 10 - Prob. 10.88PCh. 10 - Prob. 10.89PCh. 10 - Prob. 10.90PCh. 10 - Prob. 10.91PCh. 10 - Prob. 10.92PCh. 10 - Prob. 10.93PCh. 10 - Prob. 10.94PCh. 10 - Prob. 10.95PCh. 10 - Prob. 10.96PCh. 10 - Prob. 10.97PCh. 10 - Prob. 10.98PCh. 10 - Prob. 10.99PCh. 10 - Prob. 10.100PCh. 10 - Prob. 10.101PCh. 10 - Prob. 10.102PCh. 10 - Prob. 10.103PCh. 10 - Prob. 10.104PCh. 10 - Prob. 10.105PCh. 10 - Prob. 10.106PCh. 10 - Prob. 10.107PCh. 10 - Prob. 10.108PCh. 10 - Prob. 10.109PCh. 10 - Prob. 10.110PCh. 10 - Prob. 10.111PCh. 10 - Prob. 10.112PCh. 10 - Prob. 10.113PCh. 10 - Prob. 10.114PCh. 10 - Prob. 10.115PCh. 10 - Prob. 10.116PCh. 10 - Prob. 10.117PCh. 10 - Prob. 10.118PCh. 10 - Prob. 10.119PCh. 10 - The rectangular channel in Fig. P10.120 contains a...Ch. 10 - Prob. 10.121PCh. 10 - Prob. 10.122PCh. 10 - Prob. 10.123PCh. 10 - Prob. 10.124PCh. 10 - Prob. 10.125PCh. 10 - Prob. 10.126PCh. 10 - Prob. 10.127PCh. 10 - Prob. 10.128PCh. 10 - Prob. 10.1WPCh. 10 - Prob. 10.2WPCh. 10 - Prob. 10.3WPCh. 10 - Prob. 10.4WPCh. 10 - Prob. 10.5WPCh. 10 - Prob. 10.6WPCh. 10 - Prob. 10.7WPCh. 10 - Prob. 10.8WPCh. 10 - Prob. 10.9WPCh. 10 - Prob. 10.10WPCh. 10 - Prob. 10.11WPCh. 10 - Prob. 10.12WPCh. 10 - Prob. 10.13WPCh. 10 - Prob. 10.1FEEPCh. 10 - Prob. 10.2FEEPCh. 10 - Prob. 10.3FEEPCh. 10 - Prob. 10.4FEEPCh. 10 - Prob. 10.5FEEPCh. 10 - Prob. 10.6FEEPCh. 10 - Prob. 10.7FEEPCh. 10 - February 1998 saw the failure of the earthen dam...Ch. 10 - Prob. 10.2CPCh. 10 - Prob. 10.3CPCh. 10 - Prob. 10.4CPCh. 10 - Prob. 10.5CPCh. 10 - Prob. 10.6CPCh. 10 - Prob. 10.7CPCh. 10 - Prob. 10.1DPCh. 10 - Prob. 10.2DP
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