Industrial Plastics: Theory and Applications
6th Edition
ISBN: 9781285061238
Author: Lokensgard, Erik
Publisher: Delmar Cengage Learning
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Chapter 10, Problem 10.1Q
Interpretation Introduction
Interpretation: The excess material left on the product after compression molding is to be identified.
Concept introduction:
The cross-linking between the molecules take place because of heat and catalyst during the performing and molding process.
Expert Solution & Answer
Answer to Problem 10.1Q
The excess material left on the product after compression molding is flash.
Explanation of Solution
Compression molding is the molding process in which the plastic materials are formed by placing them into a cavity by heat and pressure.
The water molecules, gases, and other by-products are formed by the cross-linking reaction.
Such by-products are known as flash which is left on the product after compression molding.
Conclusion
The excess material that is left on the product after compression molding is flash which is to be removed in order to produce fine products.
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4.10
4.16 a
8. The thermal decomposition of nitric oxide at elevated temperatures
2NO → N₂+02
has been studied in a batch reactor where at temperatures below 2000K the rate
expression that applies to low conversions is:
r = kCm05 Co
At high conversions, or when the initial mixture contains a high concentration of O2 the
rate expression is given by:
r = k' Cм0.5 C15C0,5
To explain these kinetics the following chain reaction mechanism has been proposed:
Initiation:
Propagation:
2NON₂O +0
k₂
E1=272.0 kJ/mol
0+ NO O₂+ N
E₂-161.0 kJ/mol
N+NO N₂+0
E3-1.4 kJ/mol
K4
20+ MO₂+M
E4=14.0 kJ/mol
ks
Termination:
where M is any molecule capable of the energy transfer necessary to stabilize the oxygen
molecule.
Once appreciable amounts of O2 are present in the reaction mixture, the initiation
reaction that is the primary source of atomic oxygen is no longer the first reaction.
Instead, the following reaction begins to dominate the chain initiation process:
Initiation (high O2):
ks
NO +0₂ NO₂+0 E5=198.0 kJ/mol
a.…
Chapter 10 Solutions
Industrial Plastics: Theory and Applications
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