A solution having 75 mEq Na + , 35 mEq K + , 95 mEq Cl − , and 5 mEq NO 3 − is whether possible to prepare has to be determined considering charge-balance. Concept-Introduction: Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
A solution having 75 mEq Na + , 35 mEq K + , 95 mEq Cl − , and 5 mEq NO 3 − is whether possible to prepare has to be determined considering charge-balance. Concept-Introduction: Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
A solution having 75 mEq Na+, 35 mEq K+, 95 mEq Cl−, and 5 mEq NO3− is whether possible to prepare has to be determined considering charge-balance.
Concept-Introduction:
Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
(a)
Expert Solution
Answer to Problem 10.146EP
A solution having 75 mEq Na+, 35 mEq K+, 95 mEq Cl−, and 5 mEq NO3−is not possible to prepare.
Explanation of Solution
Given data is shown below:
Concentration of Na+ = 75 mEqConcentration of K+ = 25 mEqConcentration of NO3− = 5 mEqConcentration of Cl− = 95 mEq
A charge balance exists between the ions in the given electrolyte solution when the sum of Eq/L of positive ions is equal to the sum of Eq/L of negative ions.
Sum of mEq of negative ions is calculated as shown,
Here, the sum of mEq/L of positive ions is not equal to the sum of mEq/L of negative ions
Therefore,
A solution having 75 mEq Na+, 35 mEq K+, 95 mEq Cl−, and 5 mEq NO3−is not possible to prepare.
(b)
Interpretation Introduction
Interpretation:
A solution having 73 Eq K+, 55 Eq Cl−, and 18 Eq C2H3O2− is whether possible to prepare has to be determined considering charge-balance.
Concept-Introduction:
Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
(b)
Expert Solution
Answer to Problem 10.146EP
A solution having 73 Eq K+, 55 Eq Cl−, and 18 Eq C2H3O2−is possible to prepare.
Explanation of Solution
Given data is shown below:
Conc of K+= 73 Eq Conc of Cl− = 55 EqConc of C2H3O2− = 18 Eq
A charge balance exists between the ions in the given electrolyte solution when the sum of Eq/L of positive ions is equal to the sum of Eq/L of negative ions.
Sum of Eq of negative ions is calculated as shown,
Hence, the sum of Eq of positive ions is equal to the sum of Eq of negative ions
Therefore,
A solution having 73 Eq K+, 55 Eq Cl−, and 18 Eq C2H3O2−is possible to prepare.
(c)
Interpretation Introduction
Interpretation:
A solution having 750 mEq Na+ and 0.0750 Eq Cl− is whether possible to prepare has to be determined considering charge-balance.
Concept-Introduction:
Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
Unit Conversion:
1 Eq = 103 mEq
(c)
Expert Solution
Answer to Problem 10.146EP
A solution having 750 mEq Na+ and 0.0750 Eq Cl−is not possible to prepare.
Explanation of Solution
Given data is shown below:
Concentration of Na+ = 750 mEq Concentration of Cl− = 0.0750 Eq
A charge balance exists between the ions in the given electrolyte solution when the sum of Eq/L of positive ions is equal to the sum of Eq/L of negative ions.
Here, the sum of mEq/L of positive ions is not equal to the sum of mEq/L of negative ions
Therefore,
A solution having 750 mEq Na+ and 0.0750 Eq Cl−is not possible to prepare.
(d)
Interpretation Introduction
Interpretation:
A solution having 0.050 mole Na+, 0.025 mole Ca2+ and 0.075 mole Cl− is whether possible to prepare has to be determined considering charge-balance.
Concept-Introduction:
Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
Unit Conversion:
1 Eq = 103 mEq
(d)
Expert Solution
Answer to Problem 10.146EP
A solution having 0.050 mole Na+, 0.025 mole Ca2+ and 0.075 mole Cl−is not possible to prepare.
Explanation of Solution
Given data is shown below:
No. of moles of Na+ = 0.050 moleNo. of moles of Ca2+ = 0.025 moleNo. of moles of Cl− = 0.075 mole
A charge balance exists between the ions in the given electrolyte solution when the sum of Eq/L of positive ions is equal to the sum of Eq/L of negative ions.
Name
1) 3-fluoro, 1-butene
2) 2-heptene
2,3-difluoro-
1-pentene
4) 6-iodo,4-methyl-
2-decyne
5) 4,4-dibromo-
1,2-butandiol
Complete structural formula
F
-C=C-C-C-
Line formula
Condensed structural formula
N
F
CH2=CHCHFCH3
1.
Part 1: Naming Organic Compounds
он
H₁C-C-CH3
CH3
Br
CI CI
2. Br-CH-CH-CH₂
H₂C-CH-C= -CH-CH2-CH3
3.
HC-CH-CH-C-OH
5. H₂C-CH-CH₂-OH
7.
OH
4.
CH
CH₂-CH₂
6.
сно
CH-CH-CH-CH₂-CH₂
H₁₂C-CH-CH-CH-CH₁₂-CH₁₂
8.
OH
11
Organic Chemistry
Organic Nomenclature Practice
Name/Functional Group
n-butane
Formula
Structural Formula
(1) C4tt10
H3C
C-
(2) CH3CH2CH2 CH 3
H₂
-CH3
Н2
name & functional group
(1) and (2)
OH
H₁₂C
Н2
name only
(1) and (2)
name only
(1) and (2)
H₁C - = - CH₂
Н2
HC=C-C
CH3
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