Interpretation:
Out of the two given
Concept introduction:
Alpha halogenation is the halogenation at the alpha carbon atom of an
Under the acidic conditions, the first step is the protonation of carbonyl oxygen. In the second step, the acetate ions serve as a base and abstract an alpha proton from ketone; this yields an enol form. In the enol form, the alpha carbon is electron rich due to the small contribution by the resonance structure in which a negative charge and a lone pair of electrons are located on the alpha carbon. Alpha halogenation occurs only once as the electron withdrawing effect of bromine destabilizes the positive charge if the carbonyl oxygen gets protonated further. This reduces the chances of the second halogenation.

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Chapter 10 Solutions
Organic Chemistry: Principles And Mechanisms
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
