PRINT COMPANION - BUS DRIVEN INFO SYS
6th Edition
ISBN: 9781264115273
Author: BALTZAN
Publisher: MCG
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Chapter 1, Problem PIXAYKBP
To determine
Business opportunities and pitfalls with e-commerce companies like eBay, Amazon.
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Students have asked these similar questions
Find the operating point and the load line of a voltage-divider JFET biasing circuit
using the following parameters: VGS(0) = -1.3 and Vcc = 15 volts. Assume
ipss = 20 mA, RG₁ = RG2 = 10 kn, RD = 300, and Rs = 1 kn. Use Fig. 4b for
the IV characteristic of the JFET.
20nA
GS=-1.3 GS
10nA-
50
100
150
200
ID(J1)
UDS
Fig. 4b. The IV characteristics of an n-channel JFET (J113). The plots are for VGs increments of
0.05 volts. VGS(0) -1.3. The yellow and blue load lines are for examples 2 &3,
respectively.
Design the JFET circuit for the largest in swing. Use the self-bias circuit shown in
Fig. 6. Assume that VGS (0) = -1.3 and Vcc = 15 volts. Furthermore, assume that
ipss = 20 mA. Using Fig. 4b, draw the load line and identify the Q point. Explain
why this will allow the largest swing. Use ip = ipss (1-
VGS
VGS(0)
to show what
happens to i, and vps when you have a swing of 0.2 volts in vcs form its operating
point (that is, change vas by ±0.2 volts and compute the corresponding
iD and VDs).
RD
RG
Rs
0
20nA
GS=-1.3 VGS
12
10nA
-0-
Fig. 6. Circuit for Examples 2 &3.
BA-C
50
100
150
200
□ ID(J1)
UDS
Fig. 4b. The IV characteristics of an n-channel JFET (J113). The plots are for VGs increments of
0.05 volts. VGS(0) -1.3. The yellow and blue load lines are for examples 2 &3,
respectively.
please do the correct VI chrastaristics curve on excel. I am not sure if mine is correct
Chapter 1 Solutions
PRINT COMPANION - BUS DRIVEN INFO SYS
Ch. 1 - Prob. 1OCQCh. 1 - Prob. 2OCQCh. 1 - Prob. 3OCQCh. 1 - Prob. 4OCQCh. 1 - Prob. 5OCQCh. 1 - Prob. 6OCQCh. 1 - Prob. 1RQCh. 1 - Prob. 2RQCh. 1 - Prob. 3RQCh. 1 - Prob. 4RQ
Ch. 1 - Prob. 5RQCh. 1 - Prob. 6RQCh. 1 - Prob. 7RQCh. 1 - Prob. 8RQCh. 1 - Prob. 9RQCh. 1 - Prob. 10RQCh. 1 - Prob. 11RQCh. 1 - Prob. 12RQCh. 1 - Prob. 13RQCh. 1 - Prob. 14RQCh. 1 - Prob. 15RQCh. 1 - Prob. 1CCOCh. 1 - Prob. 2CCOCh. 1 - Prob. 3CCOCh. 1 - Prob. 4CCOCh. 1 - Prob. 5CCOCh. 1 - Prob. 6CCOCh. 1 - Prob. 1CCTCh. 1 - Prob. 2CCTCh. 1 - Prob. 3CCTCh. 1 - Prob. 4CCTCh. 1 - Prob. 5CCTCh. 1 - Prob. 6CCTCh. 1 - Prob. 1CBTCh. 1 - Prob. 2CBTCh. 1 - Prob. 3CBTCh. 1 - Prob. 4CBTCh. 1 - Prob. 5CBTCh. 1 - Prob. 6CBTCh. 1 - Prob. 7CBTCh. 1 - Prob. 8CBTCh. 1 - Prob. 9CBTCh. 1 - Prob. 10CBTCh. 1 - Prob. 11CBTCh. 1 - Prob. 12CBTCh. 1 - Prob. 13CBTCh. 1 - Prob. 14CBTCh. 1 - Prob. PIAYKBPCh. 1 - Prob. PIIAYKBPCh. 1 - Prob. PIIIAYKBPCh. 1 - Prob. PIVAYKBPCh. 1 - Prob. PVIAYKBPCh. 1 - Prob. PVIIAYKBPCh. 1 - Prob. PVIIIAYKBPCh. 1 - Prob. PIXAYKBPCh. 1 - Prob. PXAYKBPCh. 1 - Prob. PXIAYKBP
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- please do the correct VI chrastaristics curve on excel. I am not sure if mine is correct. Note the two curves in the picture are for both but its two tries and i dont know which is correct, and probebly both are wrong SCR (Forward Bias Condition) NO VAA VG= 0V, IG=0 mA VG= 5V, IG=4.07mA VG= 10V, IG=9.05mA VAK (V) IAK(mA) VAK (V) IAK(mA) VAK (V) IAK(mA) 1 0 0 0 0 0 0 0 2 5 0.576 4.42 mA 0.576 4.42 mA 0.576 4.43 3 10 7.99 2 0.598 9.4 0.598 9.4 4 15 14.99 0.003 0.612 14.4 0.612 14.4 5 20 19.994 0.004 0.622 19.4 0.622 19.4 6 25 0.63 24.4 0.63 24.4 0.63 24.4 4 30 0.637 29.4 0.637 29.4 0.637 29.4 8 40 0.65 39.4 0.65 39.4 0.65 39.4 9 50 0.66 49.3 0.66 49.3 0.66 49.3 10 60 0.67 59.3 0.67 59.3 0.67 59.3 11 70 0.679 69.3 0.679 69.3 SCR (Reversed Bias…arrow_forwardI tried this problem and don't know what I did wrong or how else I could approach it can you please help me out?arrow_forwardI need to make a parallel version of this sequential code.arrow_forward
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