PRINT COMPANION - BUS DRIVEN INFO SYS
6th Edition
ISBN: 9781264115273
Author: BALTZAN
Publisher: MCG
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Question
Chapter 1, Problem 6CBT
To determine
To write:
The answer of the given Questions based on the given Statement.
- Why is it so easy today for student to create start-ups while still in college?
- what would it take for you to start a business from your dorm room?
- How will this course help you prepare to start your own business?
- Research the internet and find three examples of college student start-ups.
- What's stopping you from starting your own business today? You are living in the information age, and with the power of MIS, it is easier than ever to jump into the business game with very little capital investment. Why not start your own business today?
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Students have asked these similar questions
The input reactance of an infinitesimal linear dipole of length A/60 and radius a=A/200
is given by
Xin = – 120
[In(€/a) — 1]
tan(ke)
Assuming the wire of the dipole is copper with a conductivity of 5.7 x 10' S/m,
determine at f = 1 GHz the
(a) loss resistance
(b) radiation resistance
(c) radiation efficiency
(d) VSWR when the antenna is connected to a 50-ohm line
Example
Solve the octic polynomial
2x⁸-9x⁷+20x⁶-33x⁵+46x⁴-66x³+80x²-72x+32=0
Solution
Divide by x⁴
2x⁴-9x³+20x²-33x+46-66/x + 80/x² - 72/x³ + 32/x⁴=0
Combine and bring terms
2(x⁴+16/x⁴) - 9(x³+8/x³) +20(x²+4/x²)-33(x+2/x) + 46= 0
Let use substitution
Let x+2/x =u
(x+2/x)²= u²
x²+2x*2/x + 4/x² = u²
x²+4/x²= u²-4
(x+2/x)³= x³+8/x³+3x*2/x(x+2/x)
u³= x³+8/x²+6u
x³+8/x³= u³-6u
(x²+4/x²)²= x⁴+2x²*4/x² + 16/x⁴
(u²-4)²= x⁴+16/x⁴ + 8
x⁴+16/x⁴ = (u²-4)²-8
x⁴+16/x⁴ = u⁴-8u²+8
2(u⁴-8u²+8)-9(u³-6u)+20(u²-4)-33u+46=0
Expand and simplify
2u⁴-9u³+4u²+21u-18=0
After checking
(u-1)(u-2) Are factors
Then
2u²-3u-9=0
u=3, u=-3/2
Assignment question
Solve the octic polynomial
2s⁸+s⁷+2s⁶-31s⁴-16s³-32s²-160=0 using the above example question, please explain in detail
please explain each method used, thank you
Chapter 1 Solutions
PRINT COMPANION - BUS DRIVEN INFO SYS
Ch. 1 - Prob. 1OCQCh. 1 - Prob. 2OCQCh. 1 - Prob. 3OCQCh. 1 - Prob. 4OCQCh. 1 - Prob. 5OCQCh. 1 - Prob. 6OCQCh. 1 - Prob. 1RQCh. 1 - Prob. 2RQCh. 1 - Prob. 3RQCh. 1 - Prob. 4RQ
Ch. 1 - Prob. 5RQCh. 1 - Prob. 6RQCh. 1 - Prob. 7RQCh. 1 - Prob. 8RQCh. 1 - Prob. 9RQCh. 1 - Prob. 10RQCh. 1 - Prob. 11RQCh. 1 - Prob. 12RQCh. 1 - Prob. 13RQCh. 1 - Prob. 14RQCh. 1 - Prob. 15RQCh. 1 - Prob. 1CCOCh. 1 - Prob. 2CCOCh. 1 - Prob. 3CCOCh. 1 - Prob. 4CCOCh. 1 - Prob. 5CCOCh. 1 - Prob. 6CCOCh. 1 - Prob. 1CCTCh. 1 - Prob. 2CCTCh. 1 - Prob. 3CCTCh. 1 - Prob. 4CCTCh. 1 - Prob. 5CCTCh. 1 - Prob. 6CCTCh. 1 - Prob. 1CBTCh. 1 - Prob. 2CBTCh. 1 - Prob. 3CBTCh. 1 - Prob. 4CBTCh. 1 - Prob. 5CBTCh. 1 - Prob. 6CBTCh. 1 - Prob. 7CBTCh. 1 - Prob. 8CBTCh. 1 - Prob. 9CBTCh. 1 - Prob. 10CBTCh. 1 - Prob. 11CBTCh. 1 - Prob. 12CBTCh. 1 - Prob. 13CBTCh. 1 - Prob. 14CBTCh. 1 - Prob. PIAYKBPCh. 1 - Prob. PIIAYKBPCh. 1 - Prob. PIIIAYKBPCh. 1 - Prob. PIVAYKBPCh. 1 - Prob. PVIAYKBPCh. 1 - Prob. PVIIAYKBPCh. 1 - Prob. PVIIIAYKBPCh. 1 - Prob. PIXAYKBPCh. 1 - Prob. PXAYKBPCh. 1 - Prob. PXIAYKBP
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