Concept explainers
(a)
Interpretation:
The maximum number of electrons which can hold by shell No. 1 should be determined.
Concept Introduction:
In a planetary model of an atom, negative charged electrons are arranged around the positive charged electron in a series of shells which is like orbits.
The electrons present in the outermost energy level or shell is known as valence electrons. These electrons are available for bonding and outermost shell is known as valence shell.
(b)
Interpretation:
The maximum number of electrons which can hold by shell No. 2 should be determined.
Concept Introduction:
In a planetary model of an atom, negative charged electrons are arranged around the positive charged electron in a series of shells which is like orbits.
The electrons present in the outermost energy level or shell is known as valence electrons. These electrons are available for bonding and outermost shell is known as valence shell.
(c)
Interpretation:
The way should be described by which answers to a) and b) are contained in periodic table.
Concept Introduction:
The distribution of electrons in atom into orbitals is said to be electronic configuration. The electronic configuration for every element present in the periodic table is unique or different.
Periodic Table contains periods and groups. There are 18 groups and 7 periods in the periodic table. The vertical columns are known as groups and horizontal rows are known as periods. The numbering of periods is done as 1 to 7 from top to bottom and groups are named as 1A, 2A, 3B to 8B, 1B, 2B, 3A to 8A from left to right where A represents representative elements and B represents
In periodic table, different blocks within the periodic table correspond to the s, p, d and f sublevels. Thus, on the basis of increasing atomic number in the periodic table, electronic configuration of atoms can be written.
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Chapter 1 Solutions
Organic Chemistry: A Guided Inquiry
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- Zeroth Order Reaction In a certain experiment the decomposition of hydrogen iodide on finely divided gold is zeroth order with respect to HI. 2HI(g) Au H2(g) + 12(9) Rate = -d[HI]/dt k = 2.00x104 mol L-1 s-1 If the experiment has an initial HI concentration of 0.460 mol/L, what is the concentration of HI after 28.0 minutes? 1 pts Submit Answer Tries 0/5 How long will it take for all of the HI to decompose? 1 pts Submit Answer Tries 0/5 What is the rate of formation of H2 16.0 minutes after the reaction is initiated? 1 pts Submit Answer Tries 0/5arrow_forwardangelarodriguezmunoz149@gmail.com Hi i need help with this question i am not sure what the right answers are.arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
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