Decode 01011001 using the floating point format described in figure 1.24: The rules of the floating format is, The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative. The four bits from the right are assigned as mantissa field. The remaining three bits represent the exponential field that is shown in the below table. Bit pattern value 111 3 110 2 101 1 100 0 011 − 1 101 − 2 001 − 3 000 − 4 Apply the above rules to the bit pattern 01011001 . The mantissa field of the given binary number is .1001 , shift 1 bit to the left of the decimal point then the exponential field 001 represents 1 by follow the above table.. the number becomes 1.001 Convert the number 1 into base ten representation

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Answer 1

Expert Solution & Answer

Chapter 1, Problem 36CRP

a.

Explanation of Solution

Decode 01011001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 01011001.

The mantissa field of the given binary number is .1001, shift 1 bit to the left of the decimal point then the exponential field 001 represents 1 by follow the above table.. the number becomes 1.001

Convert the number 1 into base ten representation

b.

Explanation of Solution

Decode 11001000 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 11001000.

The mantissa field of the given binary number is .1000, shift 1 bit to the left of the decimal point then the exponential field is 100 represents 0 by follow the above table.. then there is no need to shift the bit number and the number becomes 0

c.

Explanation of Solution

Decode 10101100 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 10101100.

The mantissa field of the given binary number is .1100, shift 2 bit to the left of the decimal point then the exponential field 010 represents −2 by follow the above table. The number becomes 0.001100

Convert the number 0.001100 into binary representation.

d.

Explanation of Solution

Decode 00111001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 00111001.

The mantissa field of the given binary number is .1001, shift 1 to the left of the decimal point then the exponential field 011 represents −1 by follow the above table. then number becomes 0.01001

Convert the number 0

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Change the following code so that there is always at least one way to get from the left corner to the top right, but the labyrinth is still randomized. The player starts at the bottom left corner of the labyrinth. He has to get to the top right corner of the labyrinth as fast he can, avoiding a meeting with the evil dragon. Take care that the player and the dragon cannot start off on walls. Also the dragon starts off from a randomly chosen position public class Labyrinth { private final int size; private final Cell[][] grid; public Labyrinth(int size) { this.size = size; this.grid = new Cell[size][size]; generateLabyrinth(); } private void generateLabyrinth() { Random rand = new Random(); for (int i = 0; i < size; i++) { for (int j = 0; j < size; j++) { // Randomly create walls and paths grid[i][j] = new Cell(rand.nextBoolean()); } } // Ensure start and end are…

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Make the following game user friendly with GUI, with some simple graphics. The GUI should be in another seperate class, with some ImageIcon, and Game class should be added into the pane. The following code works as this: The objective of the player is to escape from this labyrinth. The player starts at the bottom left corner of the labyrinth. He has to get to the top right corner of the labyrinth as fast he can, avoiding a meeting with the evil dragon. The player can move only in four directions: left, right, up or down. There are several escape paths in all labyrinths. The player’s character should be able to moved with the well known WASD keyboard buttons. If the dragon gets to a neighboring field of the player, then the player dies. Because it is dark in the labyrinth, the player can see only the neighboring fields at a distance of 3 units. Cell Class: public class Cell { private boolean isWall; public Cell(boolean isWall) { this.isWall = isWall; } public boolean isWall() { return…

Answer 2

Expert Solution & Answer

Chapter 1, Problem 36CRP

a.

Explanation of Solution

Decode 01011001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 01011001.

The mantissa field of the given binary number is .1001, shift 1 bit to the left of the decimal point then the exponential field 001 represents 1 by follow the above table.. the number becomes 1.001

Convert the number 1 into base ten representation

b.

Explanation of Solution

Decode 11001000 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 11001000.

The mantissa field of the given binary number is .1000, shift 1 bit to the left of the decimal point then the exponential field is 100 represents 0 by follow the above table.. then there is no need to shift the bit number and the number becomes 0

c.

Explanation of Solution

Decode 10101100 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 10101100.

The mantissa field of the given binary number is .1100, shift 2 bit to the left of the decimal point then the exponential field 010 represents −2 by follow the above table. The number becomes 0.001100

Convert the number 0.001100 into binary representation.

d.

Explanation of Solution

Decode 00111001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 00111001.

The mantissa field of the given binary number is .1001, shift 1 to the left of the decimal point then the exponential field 011 represents −1 by follow the above table. then number becomes 0.01001

Convert the number 0

Expert Solution & Answer

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Answer 3

Expert Solution & Answer

Chapter 1, Problem 36CRP

a.

Explanation of Solution

Decode 01011001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 01011001.

The mantissa field of the given binary number is .1001, shift 1 bit to the left of the decimal point then the exponential field 001 represents 1 by follow the above table.. the number becomes 1.001

Convert the number 1 into base ten representation

b.

Explanation of Solution

Decode 11001000 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 11001000.

The mantissa field of the given binary number is .1000, shift 1 bit to the left of the decimal point then the exponential field is 100 represents 0 by follow the above table.. then there is no need to shift the bit number and the number becomes 0

c.

Explanation of Solution

Decode 10101100 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 10101100.

The mantissa field of the given binary number is .1100, shift 2 bit to the left of the decimal point then the exponential field 010 represents −2 by follow the above table. The number becomes 0.001100

Convert the number 0.001100 into binary representation.

d.

Explanation of Solution

Decode 00111001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 00111001.

The mantissa field of the given binary number is .1001, shift 1 to the left of the decimal point then the exponential field 011 represents −1 by follow the above table. then number becomes 0.01001

Convert the number 0

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 1, Problem 36CRP

a.

Explanation of Solution

Decode 01011001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 01011001.

The mantissa field of the given binary number is .1001, shift 1 bit to the left of the decimal point then the exponential field 001 represents 1 by follow the above table.. the number becomes 1.001

Convert the number 1 into base ten representation

b.

Explanation of Solution

Decode 11001000 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 11001000.

The mantissa field of the given binary number is .1000, shift 1 bit to the left of the decimal point then the exponential field is 100 represents 0 by follow the above table.. then there is no need to shift the bit number and the number becomes 0

c.

Explanation of Solution

Decode 10101100 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 10101100.

The mantissa field of the given binary number is .1100, shift 2 bit to the left of the decimal point then the exponential field 010 represents −2 by follow the above table. The number becomes 0.001100

Convert the number 0.001100 into binary representation.

d.

Explanation of Solution

Decode 00111001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 00111001.

The mantissa field of the given binary number is .1001, shift 1 to the left of the decimal point then the exponential field 011 represents −1 by follow the above table. then number becomes 0.01001

Convert the number 0

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Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 1, Problem 36CRP

a.

Explanation of Solution

Decode 01011001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 01011001.

The mantissa field of the given binary number is .1001, shift 1 bit to the left of the decimal point then the exponential field 001 represents 1 by follow the above table.. the number becomes 1.001

Convert the number 1 into base ten representation

b.

Explanation of Solution

Decode 11001000 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 11001000.

The mantissa field of the given binary number is .1000, shift 1 bit to the left of the decimal point then the exponential field is 100 represents 0 by follow the above table.. then there is no need to shift the bit number and the number becomes 0

c.

Explanation of Solution

Decode 10101100 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 10101100.

The mantissa field of the given binary number is .1100, shift 2 bit to the left of the decimal point then the exponential field 010 represents −2 by follow the above table. The number becomes 0.001100

Convert the number 0.001100 into binary representation.

d.

Explanation of Solution

Decode 00111001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 00111001.

The mantissa field of the given binary number is .1001, shift 1 to the left of the decimal point then the exponential field 011 represents −1 by follow the above table. then number becomes 0.01001

Convert the number 0

Answer 8

Chapter 1, Problem 36CRP

a.

Explanation of Solution

Decode 01011001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 01011001.

The mantissa field of the given binary number is .1001, shift 1 bit to the left of the decimal point then the exponential field 001 represents 1 by follow the above table.. the number becomes 1.001

Convert the number 1 into base ten representation

Answer 9

Chapter 1, Problem 36CRP

a.

Explanation of Solution

Decode 01011001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 01011001.

The mantissa field of the given binary number is .1001, shift 1 bit to the left of the decimal point then the exponential field 001 represents 1 by follow the above table.. the number becomes 1.001

Convert the number 1 into base ten representation

Answer 10

b.

Explanation of Solution

Decode 11001000 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 11001000.

The mantissa field of the given binary number is .1000, shift 1 bit to the left of the decimal point then the exponential field is 100 represents 0 by follow the above table.. then there is no need to shift the bit number and the number becomes 0

Answer 11

b.

Explanation of Solution

Decode 11001000 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 11001000.

The mantissa field of the given binary number is .1000, shift 1 bit to the left of the decimal point then the exponential field is 100 represents 0 by follow the above table.. then there is no need to shift the bit number and the number becomes 0

Answer 12

c.

Explanation of Solution

Decode 10101100 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 10101100.

The mantissa field of the given binary number is .1100, shift 2 bit to the left of the decimal point then the exponential field 010 represents −2 by follow the above table. The number becomes 0.001100

Convert the number 0.001100 into binary representation.

Answer 13

c.

Explanation of Solution

Decode 10101100 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 10101100.

The mantissa field of the given binary number is .1100, shift 2 bit to the left of the decimal point then the exponential field 010 represents −2 by follow the above table. The number becomes 0.001100

Convert the number 0.001100 into binary representation.

Answer 14

d.

Explanation of Solution

Decode 00111001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 00111001.

The mantissa field of the given binary number is .1001, shift 1 to the left of the decimal point then the exponential field 011 represents −1 by follow the above table. then number becomes 0.01001

Convert the number 0

Answer 15

d.

Explanation of Solution

Decode 00111001 using the floating point format described in figure 1.24:

The rules of the floating format is,

The high order bit of the binary number is the sign bit. 0 is assigned as positive and 1 is assigned as negative.

The four bits from the right are assigned as mantissa field.

The remaining three bits represent the exponential field that is shown in the below table.

Bit pattern value
111 3
110 2
101 1
100 0
011 −1
101 −2
001 −3
000 −4

Apply the above rules to the bit pattern 00111001.

The mantissa field of the given binary number is .1001, shift 1 to the left of the decimal point then the exponential field 011 represents −1 by follow the above table. then number becomes 0.01001

Convert the number 0

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

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Answer 19

Ch. 1.1 - What input bit patterns will cause the following...Ch. 1.1 - In the text, we claimed that placing a 1 on the...Ch. 1.1 - Assuming that both inputs to the flip-flop in...Ch. 1.1 - a. If the output of an AND gate is passed through...Ch. 1.1 - Prob. 5QE Ch. 1.1 - Prob. 6QE Ch. 1.2 - If the memory cell whose address is 5 contains the...Ch. 1.2 - Prob. 2QE Ch. 1.2 - Design a sequence of steps that correctly...Ch. 1.2 - How many bits would be in the memory of a computer...

Bit pattern	value
111	3
110	2
101	1
100	0
011	−1
101	−2
001	−3
000	−4

Explanation of Solution

Explanation of Solution

Explanation of Solution

Explanation of Solution

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