Chapter 1, Problem 2P

Explanation of Solution

Program code:

//include the required header files

#include <iostream>

#include <string>

#include <iomanip>

#include <fstream>

//use the std namespace

using namespace std;

//create a string array MONTHARRAY

const string MONTHARRAY[12] = { " January", " February", " March", " April", " May", " June", " July", " August", " September", " October", " November", " December"};

//create a string array DAYARRAY

const string DAYARRAY[7] = {"Sun ", " Mon ", " Tue ", " Wed ", " Thu ", " Fri ", " Sat"};

int a,y,day,m,d, x;

//create integer variable month

int month;

//define two functions printMonth() and getFirst

void printMonth(int month, int startDay, int year);

int getFirst(int month, int day, int year);

//define the main() function

int main (void)

{

//prompt the user to enter the year later than 1582

cout<<"Please enter a year later than 1582: ";

//scan for the value

cin>>x;

//if the value of x is greater than 1582

if(x>1582)

{

//iterate a for loop

for (int i = 0; i<12; i++)

{

//call the methods

getFirst(i, 1, x);

printMonth(i, d, x);

}

}

//if the value of x is less than 1582

else

{

//print the statement

cout<<"That year is before 1582, please enter a better year: ";

//scan for the value

cin>>x;

}

//return 0

return 0;

}

//define the method getFirst()

int getFirst(int month, int day, int year)

{

//set the values

a = (14-month)/12;

y = year-a;

m = month+12*a-2;

d = (day+y+y/4-y/100+y/400+(31*m/12))%7;

//return the value of d

return d;

}

//define the method printMonth()

void printMonth(int month, int startDay, int year)

{

//create integer array to hold the dates

int daysInMonths[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

//create two integer variables

int copy = 1;

int counter = 1;

//print the values of M ONTHARRAY[]

cout<<MONTHARRAY[month]<<endl;

//finding leap year

//if the year is divisible by 4

if(year%4 == 0)

//set the daysInMonths[1] as 29

daysInMonths[1] = 29;

//iterate a for loop

for(int i = 0; i <=6; i++)

{

//print the values of DAYARRAY[]

cout<<DAYARRAY[i];

//if the value i is 6

if(i == 6)

//new line

cout<<endl;

    }

//iterate a while loop

while(copy<=daysInMonths[month])

{

//if the value of counter is less than or equal to startDay

if(counter <= startDay)

//print the value of left and call the method setw()

cout<<left<<setw(5)<<" ";

//if the value of counter is greater than startDay

else

{

//print the value of left and call the method setw()

cout<<left <<setw(5) <<copy;

//increment the value of copy by 1

copy++;

}

//if the counter is divisible by 7

if(counter%7 == 0 )

//print a new line

cout<<endl;

//increment the counter by 1

counter++;

}

//print a new line

cout<<endl;

}

Explanation:

The above snippet of code is used create the calendar of any year later 1582. Check the leap year. In the code,

• Include the required header files.
• Use the “std” namespace.
• Create string array “MONTHARRAY[]” and “DAYARRAY[]”.
• Create the required integer variables.
• Declare two functions “printMonth()” and “getFirst()”.
• Define “main()” function.
  • Prompt the user to enter the year later than 1582.
  • Scan for the value.
  • If the value of “x” is greater than 1582.
    • Iterate a “for” loop.
      • Call the method “getFirst()” and “printMonth()”.
  • If the value of “x” is less than 1582.
    • Prompt the statement.
    • Print the value of “x”.
  • Return “0”.
  • Define a method “printMonth()”.
    • Declare integer array, “daysInMonth[]” and variables “copy”, “counter”.
    • Print the values of the array “MONTHARRAY[]”.
    • If the year is divisible by “4”.
      • Iterate a “for” loop;
        • Print the values of the array “DAYARRAY[]”.
        • If the value of “i” is equal to “6”.
        • • Print a new line.
            • Iterate a “while” loop.
              • If the value of “counter” is less than or equal to “startDay”.
                • Print the value of “left” and “setw(5)”.
              • If the value of “counter” is greater than “startDay”.
                • Print the value of “left” and “setw(5)”.
                • Increment the value of “copy” by 1.
              • If the value of “counter” is divisible by “7”.
                • Print a new line.
              • Increment the “counter” by 1
            • Print a new line.

Output:

Please enter a year later than 1582: 1992

 January

Sun  Mon  Tue  Wed  Thu  Fri  Sat

1    2    3    4    5    6    7

8    9    10   11   12   13   14

15   16   17   18   19   20   21

22   23   24   25   26   27   28

29   30   31

 February

Sun  Mon  Tue  Wed  Thu  Fri  Sat

               1    2    3    4

5    6    7    8    9    10   11

12   13   14   15   16   17   18

19   20   21   22   23   24   25

26   27   28   29

 March

Sun  Mon  Tue  Wed  Thu  Fri  Sat

          ;&#x...