The number of protons, neutrons and electrons in the isotope of americium 2 4 1 Am needs to be determined. Concept Introduction: The atomic number is equal to the number of protons and number of electrons present in an atom. It is denoted by symbol Z. Thus, Z = n p = n e The mass number is equal to sum of number of protons and neutrons in the nucleus of atom. It is denoted by symbol A. Thus, A = n p + n n

Question

You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: xi 1. ☑ 2. H₂O хе i Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. There is no reagent that will make this synthesis work without complications. : ☐ S ☐

Answer 1

Question

Chapter 1, Problem 23P

Interpretation Introduction

Interpretation: The number of protons, neutrons and electrons in the isotope of americium ²⁴¹Am needs to be determined.

Concept Introduction: The atomic number is equal to the number of protons and number of electrons present in an atom.

It is denoted by symbol Z. Thus,

Z=np=ne

The mass number is equal to sum of number of protons and neutrons in the nucleus of atom. It is denoted by symbol A. Thus,

A=np+nn

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