Chapter 1, Problem 22QP

(a)

Interpretation Introduction

Interpretation:

The conversion of $32\text{ cm}$ into feet is to be done.

Explanation of Solution

The conversion factor for centiometer to feet is as follows.

$\begin{array}{c}1\text{ cm}=\text{0}\text{.0328084 ft}\\ 1=\frac{\text{0}\text{.0328084 ft}}{1\text{ cm}}\end{array}$

For $32\text{ cm}$ ,

$\begin{array}{c}\text{32 cm}=\frac{\text{0}\text{.0328084 ft}}{1\text{ cm}}\times \text{32 cm}\\ =\text{1}\text{.0 ft}\end{array}$

Therefore, $32\text{ cm}$ in feet is equal to $\text{1}\text{.0 ft}$ .

(b)

Interpretation Introduction

Interpretation:

The conversion of $\text{0}\text{.579 kg}$ into $\text{lb}$ is to be done.

Explanation of Solution

The conversion factor for $\text{kg}$ to $\text{lb}$ is as follows.

$\begin{array}{c}1\text{ kg}=2.20463\text{ lb}\\ 1=\frac{2.20463\text{ lb}}{1\text{ kg}}\end{array}$

For $\text{0}\text{.579 kg}$ ,

$\begin{array}{c}\text{0}\text{.579 kg}=\frac{2.20463\text{ lb}}{1\text{ kg}}\times \text{0}\text{.579 kg}\\ =\text{1}\text{.28 lb}\end{array}$

Therefore, $\text{0}\text{.579 kg}$ in $\text{lb}$ is equal to $\text{1}\text{.28 lb}$ .

(c)

Interpretation Introduction

Interpretation:

The conversion of $\text{22}\text{.70 }\mu \text{L}$ into $\text{qt}$ is to be done.

Explanation of Solution

The conversion factor for $\mu \text{L}$ to $\text{qt}$ is as follows.

$\begin{array}{c}1\mu \text{L}=0.000001056688\text{ qt}\\ 1=\frac{0.000001056688\text{ qt}}{1\mu \text{L}}\end{array}$

For $\text{22}\text{.70 }\mu \text{L}$ ,

$\begin{array}{c}\text{22}\text{.70 }\mu \text{L}=\frac{0.000001056688\text{ qt}}{1\mu \text{L}}\times \text{22}\text{.70 }\mu \text{L}\\ =2.3\times {10}^{-5}\text{ qt}\end{array}$

Therefore, $\text{22}\text{.70 }\mu \text{L}$ in $\text{qt}$ is equal to $2.3\times {10}^{-5}\text{ qt}$ .

(d)

Interpretation Introduction

Interpretation:

The conversion of $\text{9212 mm}$ into $\text{km}$ is to be done.

Explanation of Solution

The conversion factor for $\text{mm}$ to $\text{km}$ is as follows.

$\begin{array}{c}1\text{ mm}=1.0\times {10}^{-6}\text{ km}\\ 1=\frac{1.0\times {10}^{-6}\text{ km}}{1\text{ mm}}\end{array}$

For $\text{9212 mm}$ ,

$\begin{array}{c}\text{9212 mm}=\frac{1.0\times {10}^{-6}\text{ km}}{1\text{ mm}}\times \text{9212 mm}\\ =9.212\times {10}^{-3}\text{ km}\end{array}$

Therefore, $\text{9212 mm}$ to $\text{km}$ is equal to $9.212\times {10}^{-3}\text{ km}$ .

(e)

Interpretation Introduction

Interpretation:

The conversion of $\text{465 nm}$ into $\text{km}$ is to be done.

Explanation of Solution

The conversion factor for $\text{nm}$ to $\text{km}$ is as follows.

$\begin{array}{c}1\text{ nm}=1.0\times {10}^{-6}\text{ mm}\\ 1=\frac{1.0\times {10}^{-6}\text{ mm}}{1\text{ nm}}\end{array}$

For $\text{465 nm}$ ,

$\begin{array}{c}\text{465 nm}=\frac{1.0\times {10}^{-6}\text{ mm}}{1\text{ nm}}\times \text{465 nm}\\ =4.642\times {10}^{-4}\text{ mm}\end{array}$

Therefore, $\text{465 nm}$ in $\text{km}$ is equal to $4.642\times {10}^{-4}\text{ mm}$ .

(f)

Interpretation Introduction

Interpretation:

The conversion of $\text{4 ft}$ into centimeters is to be done.

Explanation of Solution

The conversion factor for feet to centimeters is as follows.

$\begin{array}{c}1\text{ cm}=\text{0}\text{.0328084 ft}\\ 1=\frac{\text{1 cm}}{\text{0}\text{.0328084 ft}}\end{array}$

For $\text{4 ft }$ ,

$\begin{array}{c}4\text{ ft}=\frac{\text{1 cm}}{\text{0}\text{.0328084 ft}}\times 4\text{ ft}\\ =\text{1}\text{.2}\times {\text{10}}^2\text{ cm}\end{array}$

Therefore, $\text{4 ft}$ in centimeters is equal to $\text{1}\text{.2}\times {\text{10}}^2\text{ cm}$ .

(g)

Interpretation Introduction

Interpretation:

The conversion of $\text{2}\text{.7 lb}$ into $\text{kg}$ is to be done.

Explanation of Solution

The conversion factor for $\text{lb}$ to $\text{kg}$ is as follows.

$\begin{array}{c}1\text{ kg}=2.20463\text{ lb}\\ 1=\frac{1\text{ kg}}{2.20463\text{ lb}}\end{array}$

For $\text{2}\text{.7 lb }$ ,

$\begin{array}{c}\text{2}\text{.7 lb }=\frac{1\text{ kg}}{2.20463\text{ lb}}\times \text{2}\text{.7 lb }\\ =\text{1}\text{.2 kg}\end{array}$

Therefore, $\text{2}\text{.7 lb }$ in $\text{kg}$ is equal to $\text{1}\text{.2 kg}$ .

(h)

Interpretation Introduction

Interpretation:

The conversion of $\text{8}\text{.320 qt}$ into $\text{m}\text{L}$ is to be done.

Explanation of Solution

The conversion factor for $\text{qt}$ to $\text{m}\text{L}$ is as follows.

$\begin{array}{c}1\text{ qt}=946.352946\text{ mL }\\ 1=\frac{946.352946\text{ mL}}{1\text{ qt}}\end{array}$

For $\text{8}\text{.320 qt}$ ,

$\begin{array}{c}\text{8}\text{.320 qt}=\frac{946.352946\text{ mL}}{1\text{ qt}}\times \text{8}\text{.320 qt}\\ =7873.6\text{ mL}\end{array}$

Therefore, $\text{8}\text{.320 qt}$ to $\text{m}\text{L}$ is equal to $7873.6\text{ mL}$ .

(i)

Interpretation Introduction

Interpretation:

The conversion of $\text{375 km}$ into feet is to be done.

Explanation of Solution

The conversion factor for $\text{km}$ to $\text{ft}$ is as follows.

$\begin{array}{c}1\text{ km}=3280.84\text{ ft }\\ 1=\frac{3280.84\text{ ft }}{1\text{ km}}\end{array}$

For $\text{375 km}$ ,

$\begin{array}{c}\text{375 km}=\frac{3280.84\text{ ft }}{1\text{ km}}\times \text{375 km}\\ =1.2\times {10}^6\text{ ft}\end{array}$

Therefore, $\text{375 km}$ in $\text{ft}$ is equal to $1.2\times {10}^6\text{ ft}$ .

(j)

Interpretation Introduction

Interpretation:

The conversion of $62\text{ g}$ into $\text{oz}$ is to be done.

Explanation of Solution

The conversion factor for $\text{g}$ to $\text{oz}$ is as follows.

$\begin{array}{c}1\text{ g}=0.035274\text{ oz }\\ 1=\frac{0.035274\text{ oz }}{1\text{ g}}\end{array}$

For $62\text{ g}$ ,

$\begin{array}{c}62\text{ g}=\frac{0.035274\text{ oz }}{1\text{ g}}\times 62\text{ g}\\ =2.2\text{ oz}\end{array}$

Therefore, $62\text{ g}$ in $\text{oz}$ is equal to $2.2\text{ oz}$ .

(k)

Interpretation Introduction

Interpretation:

The conversion of $\text{752 mL}$ into $\text{gal}$ is to be done.

Explanation of Solution

The conversion factor for $\text{mL}$ to $\text{gal}$ is as follows.

$\begin{array}{c}1\text{ mL}=0.000264172\text{ gal}\\ 1=\frac{0.000264172\text{ gal}}{1\text{ mL}}\end{array}$

For $\text{752 mL}$ ,

$\begin{array}{c}\text{752 mL}=\frac{0.000264172\text{ gal}}{1\text{ mL}}\times \text{752 mL}\\ =0.199\text{ gal}\end{array}$

Therefore, $\text{752 mL}$ in $\text{gal}$ is equal to $0.199\text{ gal}$ .