Explanation of Solution
Number of processors Arithmetic instructions L/S instructions Branch instructions Execution Time (Seconds) 1 2 .56 × 10 9 1.28 × 10 9 2 .56 × 10 9 9.6 2 1.83 × 10 9 9.14 × 10 8 2 .56 × 10 9 7.04 4 9.12 × 10 8 4.57 × 10 8 2 .56 × 10 9 3.84 8 4.57 × 10 8 2 .29 × 10 8 2 .56 × 10 9 2.24
| Number of processors | Arithmetic instructions | L/S instructions | Branch instructions | Execution Time (Seconds) |
| 1 | 9.6 | |||
| 2 | 7.04 | |||
| 4 | 3.84 | |||
| 8 | 2.24 |
The arithmetic instructions are parallelized to run over multiple cores as follows
Substitute, “
Thus, the number of arithmetic instructions with 2 processors is
Substitute, “
Thus, the number of arithmetic instructions with 4 processors is
Substitute, “
Thus, the number of arithmetic instructions with 8 processors is
The L/S instructions are parallelized to run over multiple cores as follows
Substitute, “
Thus, the number of L/S instructions with 2 processors is
Substitute, “
Thus, the number of L/S instructions with 4 processors is
Substitute, “
Thus, the number of L/S instructions with 8 processors is
The total execution time of the program can be calculated using the following formula
Substitute, “2” for “CPI of arithmetic instructions”, “12” for “CPI of L/S instructions”, “5” for “CPI of branch instructions”,, “
Thus, the total execution time of the program with 1 processor is “10.88 seconds”.
Substitute, “2” for “CPI of arithmetic instructions”, “12” for “CPI of L/S instructions”, “5” for “CPI of branch instructions”,, “
Thus, the total execution time of the program with 1 processor is “7.95 seconds”.
Substitute, “2” for “CPI of arithmetic instructions”, “12” for “CPI of L/S instructions”, “5” for “CPI of branch instructions”,, “
Thus, the total execution time of the program with 1 processor is “4.29 seconds”.
Substitute, “2” for “CPI of arithmetic instructions”, “12” for “CPI of L/S instructions”, “5” for “CPI of branch instructions”,, “
Thus, the total execution time of the program with 1 processor is “2.47 seconds”.
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Chapter 1 Solutions
COMPUTER ORGANIZATION+DESIGN >I<
- (c) Consider the following sequence of rotations: 1) Rotate by 130° about the world z-axis 2) Rotate by 45° about the current x-axis 3) Rotate by -30° about the world/fixed y-axis Compute the resulting overall rotation matrix R. Notice that you need to provide the numerical solution to the matrix R. (d) Find R giving the following rotation matrices. 1 0 0 1 √√3 го о 0 0 R₁₁ = 2 R₁ = 0 1 0 1 0 0 0 2 2arrow_forwardProblem 1: Complete the following problems. (a) Let {A}, {B}, {C}, {U} denote four frames. Given the transformations HU, HR, HG, find the transformation matrix H. Yeah York Austri, R. Noude that you need to provide (b) Frame {A} has three axes denoted by RA, PA, 2A, respectively. Frame {B} is obtained by rotating about YA by 30° and then subsequently translating along A axis by 2 units. Find the resulting homogeneous transformation matrix HA.arrow_forwardProblem 2: Find the ZYZ Euler angle parameterization of the following rotation matrix. Student need to provide both sets of solutions. -0.47 -0.66 0.581 R = 0.83 0.56 0.04 0.29 0.5 0.81]arrow_forward
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I need help fixing errors on the VHDL so that the counter counts up from 1 to 6 of both files, as the attached image shows when compiled. Counter_1_to_6.vhdl: library IEEE;use IEEE.STD_LOGIC_1164.ALL;use IEEE.STD_LOGIC_ARITH.ALL;use IEEE.STD_LOGIC_UNSIGNED.ALL; entity Counter_1_to_6 is Port ( clk : in STD_LOGIC; -- Clock input reset : in STD_LOGIC; -- Asynchronous reset count : out STD_LOGIC_VECTOR (2 downto 0) -- 3-bit output (1 to 6) );end Counter_1_to_6; architecture Behavioral of Counter_1_to_6 is signal counter_reg : STD_LOGIC_VECTOR (2 downto 0) := "001"; -- Start at 1begin process(clk, reset) begin if reset = '1' then counter_reg <= "001"; -- Reset to 1 elsif rising_edge(clk) then if counter_reg =…arrow_forwardI need help with this problem, and an explanation for the solution is described below (Fundamentals of Computer Engineering: ModelSim - standard edition). I need help modifying the below codes of "VHDL so that the counter counts up from 1 to 7" of both files into "VHDL to design a counter to count up from 1 to 6". (Fundamentals of Computer Engineering: ModelSim - standard edition). Counter_1_to_7.vhdl: library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.STD_LOGIC_ARITH.ALL; use IEEE.STD_LOGIC_UNSIGNED.ALL; entity Counter_1_to_7 is Port ( clk : in STD_LOGIC; -- Clock input reset : in STD_LOGIC; -- Asynchronous reset count : out STD_LOGIC_VECTOR (2 downto 0) -- 3-bit output (1 to 7) ); end Counter_1_to_7; architecture Behavioral of Counter_1_to_7 is signal counter_reg : STD_LOGIC_VECTOR (2 downto 0) := "001"; -- Start at 1 begin process(clk, reset) begin if reset = '1' then counter_reg <= "001"; -- Reset to 1 elsif rising_edge(clk) then if…arrow_forwardCREATE DATABASE H Vybo PAP PT AUTO INCREMENT PEMARY FLY CHARDOX Age N GIMM ARCH Contacte WCHO CREATE TABLE Typ AUTO INCEMENT MARY CREATE SALE Patan T GN AUTO CEMENT PAMARY DDATE Test T CHAD FOREIGN KEY REFERENCES TORGNY (REFERENCES DNA MOMENT MARY WEC G DECIMAIS COCIMAL DECIMALIA MCDOWALS WECO FORDONKEY COREFERENCES CREATE TABLE Does DUO INCREMENT PRMANY P DATE Dugan D Tata TEXT FORDONKEY OFFENCES CREATE TABLE CREATE TABLE eaten AUTO INCREMENT PRIMARY KEY. St End W Cum ARCHA FOREIGN KEY (Patient REFERENCES P CREATE TABLE DNT AUTO INCREMENT PRIMARY VARCHAR Преспавлявал масн Departe ICHARITOO Contact Info WOWRIS CHEAT TABLE Appointments Apport DIN AUTONEMENT PRIMARY D INT Doctor D INT Aparent DevCATE Explain these in detail and why you used this IN NIO Nine, Age, Gender, Address Contact Medical Hond HALLES Ca 30 M. 10th St. 555 123, atory of meer 22 F20 Street, 555-5678 Noagnificant cal INSERT INTO Test, on est Te Narel VALUES гово Tog bom test 0 Det type D R VALUES 112024-12-15, 1, N…arrow_forwardI need help with this problem, and an explanation for the solution is described below (Fundamentals of Computer Engineering: ModelSim - standard edition). I need help fixing errors on the VHDL so that the counter counts up from 1 to 7 of both files, as the attached image shows when compiled. Counter_1_to_7.vhdl: library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.STD_LOGIC_ARITH.ALL; use IEEE.STD_LOGIC_UNSIGNED.ALL; entity Counter_1_to_7 is Port ( clk : in STD_LOGIC; -- Clock input reset : in STD_LOGIC; -- Asynchronous reset count : out STD_LOGIC_VECTOR (2 downto 0) -- 3-bit output (1 to 7) ); end Counter_1_to_7; architecture Behavioral of Counter_1_to_7 is signal counter_reg : STD_LOGIC_VECTOR (2 downto 0) := "001"; -- Start at 1 begin process(clk, reset) begin if reset = '1' then counter_reg <= "001"; -- Reset to 1 elsif rising_edge(clk) then if counter_reg = "111" then counter_reg <= "001"; -- Wrap around to 1 after 7 else counter_reg <= counter_reg + 1; -- Increment…arrow_forwardTasks 4 • • . • • Task 1: Create a 'Movie' class and update its rating using keyword arguments. Task 2: Create a 'Student' class and change the major using positional and keyword arguments. Task 3: Create a 'ShoppingCart' class and add items using positional arguments. 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Ensure set_count only accepts non-negative integers, and add increment()', decrement()', and 'reset()` methods for control.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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