Chapter 1, Problem 1.8.1E

Explanation of Solution

Given,

The Pentium 4 Prescott processor includes 3.6 GHz of frequency and 1.25 V of voltage with 10 W and 90 W of static power and dynamic power respectively.

The Core i5 Ivy Bridge processor includes 3.4 GHz of frequency and 0.9 V of voltage with 30 W and 40 W of static power and dynamic power respectively.

The capacitive loads of the processor can be calculated using the following formula is given below:

$\text{C}\text{=}\frac{\text{2}\text{×}\text{dynamic}\text{power}}{{\text{(voltage}}^{\text{2}}\text{×}\text{frequency)}}$

Substitute, “90” for “dynamic power”, “1.25” for “voltage” and “$\text{3}\text{.6}\text{×}{\text{10}}^{\text{6}}$” for “frequency” in the above formula is given below:

$\begin{array}{c}\text{C}\text{=}\frac{\text{2}\text{×}\text{90}}{{\text{(1}\text{.25)}}^{\text{2}}\text{×}\text{3}\text{.6}\text{×}{\text{10}}^{\text{6}}}\\ \text{=}\text{3}\text{.2}\text{×}{\text{10}}^{\text{-8}}\end{array}$

Thus, the capacitive load of the Pentium 4 Prescott processor is $\text{3}$