International Edition---engineering Mechanics: Statics 4th Edition
4th Edition
ISBN: 9781305856240
Author: Pytel
Publisher: Cengage
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Chapter 1, Problem 1.71P
The force
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Chapter 1 Solutions
International Edition---engineering Mechanics: Statics 4th Edition
Ch. 1 - A person weighs 30 lb on the moon, where...Ch. 1 - The radius and length of a steel cylinder are 40...Ch. 1 - Convert the following: (a) 400lbft to knm; (b)...Ch. 1 - A compact car travels 30 mi on one gallon of gas....Ch. 1 - The kinetic energy of a car of mass m moving with...Ch. 1 - In a certain application, the coordinate a and the...Ch. 1 - When a force F acts on a linear spring, the...Ch. 1 - In some applications dealing with very high...Ch. 1 - A geometry textbook gives the equation of a...Ch. 1 - A differential equation is d2ydt2=Ay2+Byt where y...
Ch. 1 - The position coordinate x of a particle is...Ch. 1 - A differential equation encountered in the...Ch. 1 - Determine the dimensions of constants A and B far...Ch. 1 - The typical power output of a compact car engine...Ch. 1 - Two 12-kg spheres are placed 400 mm apart. Express...Ch. 1 - Two identical spheres of radius 8 in. and weighing...Ch. 1 - A man weighs 170 lb on the surface of the earth....Ch. 1 - Use Eq. (1.4) to show that the weight of an object...Ch. 1 - Plot the earths gravitational acceleration g(m/s2)...Ch. 1 - Find the elevation h (km) where the weight of an...Ch. 1 - Calculate the gravitational force between the...Ch. 1 - The magnitudes of the two velocity vectors are...Ch. 1 - Determine the magnitudes of vectors v1 and v2 so...Ch. 1 - The pole AB is held up by the rope attached to B....Ch. 1 - Resolve the 20-kN force into components along the...Ch. 1 - The velocity vector of the boat has two...Ch. 1 - Two members of a truss apply the forces shown to...Ch. 1 - Two members of a truss apply the forces shown to...Ch. 1 - Determine the resultant of the position vectors A...Ch. 1 - Resolve the position vector A of the car (measured...Ch. 1 - Resolve the 360-lb force into components along the...Ch. 1 - The supporting cables AB and AC are oriented so...Ch. 1 - The two forces shown act on the structural member...Ch. 1 - The resultant of the two forces has a magnitude of...Ch. 1 - The forces acting on the bob of the pendulum are...Ch. 1 - A surveyor sights a target at C from points A and...Ch. 1 - Knowing that the resultant of the two forces is...Ch. 1 - To move the oil drum, the resultant of the three...Ch. 1 - The resultant of the 50-Ib and 30-lb forces is R....Ch. 1 - Obtain the rectangular representation of the force...Ch. 1 - The length of the position vector r is 240 mm....Ch. 1 - Determine the rectangular components of the 560-lb...Ch. 1 - The coordinates of points A and B are (-3, 0, 2)...Ch. 1 - The slider travels along the guide rod AB with the...Ch. 1 - Find the rectangular representation of the force...Ch. 1 - The magnitude of the force F is 160 lb. Find its...Ch. 1 - A rifle at A is fired at a target at B. If the...Ch. 1 - The pole OB is subjected to the 6004b force at B....Ch. 1 - The cables AB and AC are attached to the frame...Ch. 1 - The two forces are applied to the end of the boom...Ch. 1 - The magnitudes of the three forces are...Ch. 1 - Given that P=120lb and Q=130lb, find the...Ch. 1 - Knowing that P=90lb and that the resultant of P...Ch. 1 - If R is the resultant of the forces P and Q, find...Ch. 1 - The force R is the resultant of P and 0. Determine...Ch. 1 - The vertical post is secured by three cables. The...Ch. 1 - Compute the dot product A - B for each of the...Ch. 1 - Compute the cross product C=AB for each of the...Ch. 1 - Given r=4i6j+2km (position vector) F=20i+40j30kN...Ch. 1 - Compute AB and CB for the position vectors shown.Ch. 1 - Use the dot product to find the angle between the...Ch. 1 - Use the dot product to find the angle between the...Ch. 1 - Let A and B be two nonparallel vectors that lie in...Ch. 1 - Determine (a) the angle between the position...Ch. 1 - Find a unit vector that is perpendicular to both...Ch. 1 - The three points A(0,2,2),B(1,4,1), and C(3,0,0)...Ch. 1 - For the position vectors P and Q shown, determine...Ch. 1 - Compute the orthogonal Component of F=6i+20j12klb...Ch. 1 - Compute the value of the scalar a for which the...Ch. 1 - Resolve A=3i+5j4k in. into two vector...Ch. 1 - The force F=5i+12j+4k lb is applied to the handle...Ch. 1 - Determine the value of the scalar a if the...Ch. 1 - Resolve the force F=20i+30j+50klb into two...Ch. 1 - It can be show that a plane area may he...Ch. 1 - The coordinates of the corners of a triangle ABC...Ch. 1 - Show that |abc| equals the volume of a...
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- 1. 1.25 m³ of saturated liquid water at 225°C is expanded isothermally in a closed system until its quality is 75 percent. Determine the total work produced by this expansion, in kJ.arrow_forwardAn undamped single-degree-of-freedom system is subjected to dynamic excitation as shown in Figure 1.• System properties: m = 1, c = 0, k = (6π)2.• Force excitation: p(t) = posin(ωt) where po = 9 and ω = 2π.• Initial conditions: u(t = 0) = 0 and ̇u(t = 0) = 0.Please, complete Parts (a) through (d) using any computational tool of your preference. The preferred toolis MATLAB. Print and turn in a single pdf file that will include your code/calculations and your plots.(a) Generate the solution using a linear interpolation of the load over each time step (note that hereyou can use the undamped coefficients). Plot the displacement response for the first 4 seconds andcompare to the exact closed form solution. Repeat using the following time step sizes, ∆t = 0.01,0.05, 0.15, 0.20 seconds. Include the closed form solution and the solutions for different ∆t values in asingle plot. Please, provide your observations by comparing the closed form solution with the solutionsderived using the four…arrow_forwardAssume multiple single degree of freedom systems with natural periods T ∈ [0.05, 2.00] seconds with in-crement of period dT = 0.05 seconds. Assume three cases of damping ratio: Case (A) ξ = 0%; Case (B)ξ = 2%; Case (C) ξ = 5%. The systems are initially at rest. Thus, the initial conditions are u(t = 0) = 0 anḋu(t = 0) = 0. The systems are subjected to the base acceleration that was provided in the ElCentro.txt file(i.e., first column). For the systems in Case (A), Case (B), and Case (C) and for each natural period computethe peak acceleration, peak velocity, and peak displacement responses to the given base excitation. Please,use the Newmark method for β = 1/4 (average acceleration) to compute the responses. Create threeplots with three lines in each plot. The first plot will have the peak accelerations in y-axis and the naturalperiod of the system in x-axis. The second plot will have the peak velocities in y-axis and the natural periodof the system in x-axis. The third plot will have…arrow_forward
- Both portions of the rod ABC are made of an aluminum for which E = 70 GPa. Based on the given information find: 1- deformation at A 2- stress in BC 3- Total strain 4- If v (Poisson ratio is 0.25, find the lateral deformation of AB Last 3 student ID+ 300 mm=L2 724 A P=Last 2 student ID+ 300 KN 24 24 Diameter Last 2 student ID+ 15 mm Last 3 student ID+ 500 mm=L1 724 C B 24 Q=Last 2 student ID+ 100 KN 24 Diameter Last 2 student ID+ 40 mmarrow_forwardQ2Two wooden members of uniform cross section are joined by the simple scarf splice shown. Knowing that the maximum allowable tensile stress in the glued splice is 75 psi, determine (a) the largest load P that can be safely supported, (b) the corresponding shearing stress in the splice. น Last 1 student ID+5 inch=W =9 4 L=Last 1 student ID+8 inch =12 60° P'arrow_forwardQ4 The two solid shafts are connected by gears as shown and are made of a steel for which the allowable shearing stress is 7000 psi. Knowing the diameters of the two shafts are, respectively, dBC determine the largest torque Tc that can be applied at C. 4 and dEF dBC=Last 1 student ID+3 inch dEF=Last 1 student ID+1 inch 7 R=Last 1 Student ID+5 inch 9 R B Tc 2.5 in. E TF Harrow_forward
- Experiment تكنولوجيا السيارات - Internal Forced convenction Heat transfer Air Flow through Rectangular Duct. objective: Study the convection heat transfer of air flow through rectangular duct. Valve Th Top Dead Centre Exhaust Valve Class CP. N; ~ RIVavg Ti K 2.11 Te To 18.8 21.3 45.8 Nath Ne Pre Calculations:. Q = m cp (Te-Ti) m: Varg Ac Acca*b Q=hexp As (Ts-Tm) 2 2.61 18.5 20.846.3 Tm = Te-Ti = 25 AS-PL = (a+b)*2*L Nu exp= Re-Vavy D heep Dh k 2ab a+b Nu Dh the- (TS-Tm) Ts. Tmy Name / Nu exp Naxe بب ارتدان العشريarrow_forwardProcedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findarrow_forwardProcedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forward
- Procedure: 1- Cartesian system, 2D3D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D ∑Fx=0 ∑Fy=0 ∑Fz=0 ∑Mx=0 ∑My=0 ΣMz=0 2D ΣFx=0 ΣFy=0 ΣMz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of thearrow_forwardProcedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
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