Chapter 1, Problem 1.39QP

(a)

Interpretation Introduction

Interpretation:

Given set of unit conversions have to be given.

Given data:

$\text{242}\text{lb}$

General unit conversions

$\begin{array}{l}\text{1lb}\text{=}\text{453}\text{.6}\text{g}\\ \text{1}\text{×}{\text{10}}^{\text{-3}}\text{g}\text{=}\text{1}\text{mg}\end{array}$

Conversion of pounds to milligram unit

$\begin{array}{l}\text{242}\text{lb}\text{×}\frac{\text{453}\text{.6}\text{grams}}{\text{1 lb}}\text{×}\frac{\text{1}\text{mg}}{\text{1}\text{×}{\text{10}}^{\text{-3}}\text{grams}}\\ \text{=}\text{109771}\text{.2}\text{×}{\text{10}}^{\text{3}}\text{mg}\\ \text{=}\text{1}\text{.10}\text{×}{\text{10}}^{\text{8}}\text{mg}\end{array}$

(b)

Interpretation Introduction

Interpretation:

Given set of unit conversions have to be given.

Given data:

$\text{68}\text{.3}{\text{cm}}^{\text{3}}$

General unit conversions

$\text{100}\text{centimetre}\text{=}\text{1}\text{meter}$

Conversion of cubic centimetre to cubic metre unit

$\begin{array}{l}\text{68}\text{.3}{\text{cm}}^{\text{3}}\text{×}{\left(\frac{\text{1 m}}{\text{100}\text{cm}}\right)}^{\text{3}}\\ \text{=}\text{68}\text{.3}\text{×}{\text{10}}^{\text{-6}}{\text{m}}^{\text{3}}\\ \text{=}\text{6}\text{.83}\text{×}{\text{10}}^{\text{-5}}{\text{m}}^{\text{3}}\end{array}$

(c)

Interpretation Introduction

Interpretation:

Given set of unit conversions have to be given.

Given data:

$\text{7}\text{.2}{\text{m}}^{{}^{\text{3}}}$

General unit conversions

$\begin{array}{l}\text{1}\text{×}{\text{10}}^{\text{-2}}\text{meter}\text{=}\text{1}\text{centimetre}\\ \text{1000}{\text{cm}}^{\text{3}}\text{=}\text{1}\text{litre}\end{array}$

Conversion of cubic meter to litre unit

$\begin{array}{l}\text{7}\text{.2}{\text{m}}^{\text{3}}\text{×}{\left(\frac{\text{1}\text{cm}}{\text{1}\text{×}{\text{10}}^{\text{-2}}\text{ m}}\right)}^{\text{3}}\text{×}\frac{\text{1}\text{L}}{\text{1000}{\text{cm}}^{\text{3}}}\\ \text{=}\text{7}\text{.2}\text{×}{\text{10}}^{\text{3}}\text{L}\end{array}$

(d)

Interpretation Introduction

Interpretation:

Given set of unit conversions have to be given.

Given data:

$\text{28}\text{.3}\text{μg}$

General unit conversions

$\begin{array}{l}\text{1}\text{μg}\text{=}\text{1}\text{×}{\text{10}}^{\text{-6}}\text{g}\\ \text{453}\text{.6}\text{g}\text{=}\text{1}\text{lb}\end{array}$

Conversion of microgram to pounds unit

$\begin{array}{l}\text{28}\text{.3}\text{μg}\text{×}\frac{\text{1}\text{×}{\text{10}}^{\text{-6}}\text{ g}}{\text{1}\text{μg}}\text{×}\frac{\text{1}\text{lb}}{\text{453}\text{.6}\text{g}}\\ \text{=}\text{6}\text{.24}\text{×}{\text{10}}^{\text{-8}}\text{lb}\end{array}$