ORG CHEM W/ EBOOK & SW5 + STUDY GUIDE
2nd Edition
ISBN: 9780393666144
Author: KARTY
Publisher: NORTON
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Question
Chapter 1, Problem 1.2P
Interpretation Introduction
(a)
Interpretation:
The number of protons and electrons in the anion of the carbon atom having net charge
Concept introduction:
The number of protons in the nucleus of an atom is called its
Interpretation Introduction
(b)
Interpretation:
The number of protons and electrons in a cation of the oxygen atom having net charge
Concept introduction:
The total number of protons in the atom’s nucleus is its atomic number. In a neutral atom, the number of protons and electrons is equal. Ions are formed by the loss or gain of electrons from the neutral atom. If an atom gains one or more electrons, the ion formed is called an anion. The charge on the anion is equal to the number of electrons gained. If an atom loses one or more electrons, the ion formed is called a cation. The charge on the cation is equal to the number of electrons lost.
Interpretation Introduction
(c)
Interpretation:
The number of protons and electrons in the anion of an oxygen atom having net charge -1 is to be determined.
Concept introduction:
The total number of protons in the atom’s nucleus is its atomic number. In a neutral atom, the number of protons and electrons is equal. Ions are formed by the loss or gain of electrons from the neutral atom. If an atom gains one or more electrons, the ion formed is called an anion. The charge on the anion is equal to the number of electrons gained. If an atom loses one or more electrons, the ion formed is called a cation. The charge on the cation is equal to the number of electrons lost.
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⚫ worksheets.beyondlabz.com
5 (a). Using the peak information you listed in the tables for
both structures, assign each peak to that portion of the
structure that produces the peak in the NMR spectrum. Draw
this diagram on your own sheet of paper and attach the sketch
of your drawing to this question.
Question 6
5 (b). Using the peak information you listed in the tables for
both structures, assign each peak to that portion of the
structure that produces the peak in the NMR spectrum. Draw
this diagram on your own sheet of paper and attach the sketch
of your drawing to this question.
Question 7
6. Are there any differences between the spectra you obtained
in Beyond Labz and the predicted spectra? If so, what were
the differences?
<
2. Predict the NMR spectra for each of these two
compounds by listing, in the NMR tables below, the
chemical shift, the splitting, and the number of
hydrogens associated with each predicted peak. Sort the
peaks from largest chemical shift to lowest.
**Not all slots must be filled**
Peak
Chemical Shift (d)
5.7
1
Multiplicity
multiplate
..........
5.04
double of doublet
2
4.98
double of doublet
3
4.05
doublet of quartet
4
5
LO
3.80
quartet
1.3
doublet
6
Peak
Chemical Shift (d)
Multiplicity
Chapter 1 Solutions
ORG CHEM W/ EBOOK & SW5 + STUDY GUIDE
Ch. 1 - Prob. 1.1PCh. 1 - Prob. 1.2PCh. 1 - Prob. 1.3PCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. 1.8PCh. 1 - Prob. 1.9PCh. 1 - Prob. 1.10P
Ch. 1 - Prob. 1.11PCh. 1 - Prob. 1.12PCh. 1 - Prob. 1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.15PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - Prob. 1.23PCh. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Prob. 1.27PCh. 1 - Prob. 1.28PCh. 1 - Prob. 1.29PCh. 1 - Prob. 1.30PCh. 1 - Prob. 1.31PCh. 1 - Prob. 1.32PCh. 1 - Prob. 1.33PCh. 1 - Prob. 1.34PCh. 1 - Prob. 1.35PCh. 1 - Prob. 1.36PCh. 1 - Prob. 1.37PCh. 1 - Prob. 1.38PCh. 1 - Prob. 1.39PCh. 1 - Prob. 1.40PCh. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - Prob. 1.43PCh. 1 - Prob. 1.44PCh. 1 - Prob. 1.45PCh. 1 - Prob. 1.46PCh. 1 - Prob. 1.47PCh. 1 - Prob. 1.48PCh. 1 - Prob. 1.49PCh. 1 - Prob. 1.50PCh. 1 - Prob. 1.51PCh. 1 - Prob. 1.52PCh. 1 - Prob. 1.53PCh. 1 - Prob. 1.54PCh. 1 - Prob. 1.55PCh. 1 - Prob. 1.56PCh. 1 - Prob. 1.57PCh. 1 - Prob. 1.58PCh. 1 - Prob. 1.59PCh. 1 - Prob. 1.60PCh. 1 - Prob. 1.61PCh. 1 - Prob. 1.62PCh. 1 - Prob. 1.63PCh. 1 - Prob. 1.64PCh. 1 - Prob. 1.65PCh. 1 - Prob. 1.66PCh. 1 - Prob. 1.67PCh. 1 - Prob. 1.68PCh. 1 - Prob. 1.69PCh. 1 - Prob. 1.70PCh. 1 - Prob. 1.71PCh. 1 - Prob. 1.72PCh. 1 - Prob. 1.73PCh. 1 - Prob. 1.74PCh. 1 - Prob. 1.75PCh. 1 - Prob. 1.76PCh. 1 - Prob. 1.77PCh. 1 - Prob. 1.78PCh. 1 - Prob. 1.79PCh. 1 - Prob. 1.80PCh. 1 - Prob. 1.81PCh. 1 - Prob. 1.82PCh. 1 - Prob. 1.1YTCh. 1 - Prob. 1.2YTCh. 1 - Prob. 1.3YTCh. 1 - Prob. 1.4YTCh. 1 - Prob. 1.5YTCh. 1 - Prob. 1.6YTCh. 1 - Prob. 1.7YTCh. 1 - Prob. 1.8YTCh. 1 - Prob. 1.9YTCh. 1 - Prob. 1.10YTCh. 1 - Prob. 1.11YTCh. 1 - Prob. 1.12YTCh. 1 - Prob. 1.13YTCh. 1 - Prob. 1.14YTCh. 1 - Prob. 1.15YTCh. 1 - Prob. 1.16YTCh. 1 - Prob. 1.17YT
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