Explanation Given: I L 1 = 100 μ A R L 1 = 100 k Ω I L 2 = 500 μ A R L 2 = 10 k Ω Calculation: Draw the circuit diagram for R L 1 . Fig: circuit diagram for R L 1 From the circuit shown above load, current is given by I L 1 = V t h R t h + R L 1 plugging values 100 × 10 − 6 = V t h R t h + 100 × 10 3 1 Similarly, draw the circuit diagram for R L 2 Fig: circuit diagram for R L 2 From the circuit shown above, load current is given by I L 2 = V t h R t h + R L 2 plugging values 500 × 10 − 6 = V t h R t h + 10 × 10 3 2 Divide both equations 100 × 10

Microelectronic Circuits (the Oxford Series In Electrical And Computer Engineering)

8th Edition

ISBN: 9780190853464

Author: Adel S. Sedra, Kenneth C. (kc) Smith, Tony Chan Carusone, Vincent Gaudet

Publisher: Oxford University Press

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Chapter 1, Problem 1.26P

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Thevenin’s voltage Norton current and source resistance.

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Chapter 1 Solutions

Microelectronic Circuits (the Oxford Series In Electrical And Computer Engineering)

Ch. 1.1 - Prob. 1.1E Ch. 1.1 - Prob. 1.2E Ch. 1.1 - Prob. 1.3E Ch. 1.1 - Prob. 1.4E Ch. 1.2 - Prob. 1.5E Ch. 1.2 - Prob. 1.6E Ch. 1.2 - Prob. 1.7E Ch. 1.2 - Prob. 1.8E Ch. 1.3 - Prob. 1.9E Ch. 1.4 - Prob. 1.10E

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Thevenin’s voltage Norton current and source resistance.

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Thevenin’s voltage Norton current and source resistance.

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Chapter 1 Solutions