Chapter 1, Problem 1.1P

(a)

To determine

The current in given resistor using ohm’s law.

Answer to Problem 1.1P

  $I=0.5mA$

Explanation of Solution

Given:

  $\begin{array}{l}R=1\text{k}\Omega \\ V=0.5\text{V}\end{array}$

Calculation:

According to ohm’s law, the formula of current flowing through a resistor is given by

  $I=\frac{V}{R}$

Plugging given values:

  $\begin{array}{l}I=\frac{0.5}{1\times {10}^3}\\ I=0.5\times {10}^{-3}\\ I=0.5mA\end{array}$

(b)

To determine

The resistance for given values of current and voltage using ohm’s law.

Answer to Problem 1.1P

  $R=2\text{k}\Omega$

Explanation of Solution

Given:

  $\begin{array}{l}V=2\text{V}\\ I=1mA\end{array}$

Calculation:

According to ohm’s law, the formula of resistance is given by

  $R=\frac{V}{I}$

Plugging given values:

  $\begin{array}{l}R=\frac{2}{1\times {10}^{-3}}\\ R=2\times {10}^3\\ R=2\text{k}\Omega \end{array}$

(c)

To determine

The voltage for given values of current and resistance using ohm’s law.

Answer to Problem 1.1P

  $V=2\text{V}$

Explanation of Solution

Given:

  $\begin{array}{l}R=20\text{k}\Omega \\ I=0.1mA\end{array}$

Calculation:

According to ohm’s law, the formula of current flowing through a resistor is given by

  $V=IR$

Plugging given values:

  $\begin{array}{l}V=0.1\times {10}^{-3}\times 20\times {10}^3\\ V=2\text{V}\end{array}$

(d)

To determine

The current for given values of voltage and resistance using ohm’s law.

Answer to Problem 1.1P

  $I=0.2mA$

Explanation of Solution

Given:

  $I=\frac{V}{R}$

Calculation:

According to ohm’s law, the formula of current flowing through a resistor is given by

  $I=\frac{V}{R}$

Plugging given values:

  $\begin{array}{l}I=\frac{2}{100}\\ I=2\times {10}^{-2}\\ I=0.2mA\end{array}$