Chapter 1, Problem 1.136QP

Interpretation Introduction

Interpretation:

The densities of lead, uranium and platinum bars has to be calculated if each of the bar had the same mass and volume of lead is $\text{6}\text{.36}{\text{cm}}^{\text{3}}$, volume of uranium is $\text{3}\text{.97}{\text{cm}}^{\text{3}}$ and volume of platinum is $\text{1}\text{.00}\text{×}{\text{10}}^{\text{2}}{\text{cm}}^{\text{3}}$.  The one with lower density and the one with higher density has to be labelled.

Concept Introduction:

Density:

The ratio of mass of a sample to its volume is said to be the density.

  $\text{Density = }\frac{\text{mass}}{\text{volume}}$